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2 years ago

If PQ = 7 and PR = 32, find QR.* use diagram a.) 39 b.) 25 c.) 28 d.) 30

Mathematics

1 answer:

lukranit [14]2 years ago

4 0

Answer:

Step-by-step explanation:

I think answer is B. Because 32 mjnus 7 is 25.

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Clay and Clod thought of the same number. Clay divided the number by 7 to that number and added 14 to the result. He got 23. Clo

Nesterboy [21]

Clod would get 11, because the number they both thought of was 63

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1 year ago

Leena walked 2/3 of a mile What is 2/3 written as a sum of unit fractions with the denominator of nine

aliya0001 [1]

Bear in mind that multiplying anything, and anything whatsoever by 1, has a product of the anything itself.

so, let's multiply 2/3 by 1 then and check about,

$\bf \cfrac{same}{same}=1\qquad thus\cfrac{2}{3}\cdot 1\implies \cfrac{2}{3}\cdot \cfrac{3}{3}\implies \cfrac{6}{9}
\\\\\\
\textit{now, we can split that and write it as a sum}\implies \cfrac{1+5}{9}\implies \cfrac{1}{9}+\cfrac{5}{9}$

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2 years ago

Priscilla’s grandmother’s fruit salad recipe calls for one part apple, one part orange, four parts strawberry, two parts cherry,

Kryger [21]

There are 11 parts of fruit: 4-strawberry, 3- grape, 2, cherry, 1- apple, 1-orange

4/11 from the entine quantity of fruits- strawberry
3/11-grapes
2/11- cherries
1/11- apples
1/11- oranges } ⇒ the quantity of oranges and apples are equal

The biggest part of the fruit- 4/11 - are strawberries
4/11>3/11>2/11>1/11
the smallest part of the fruit- apples and oranges

8 0

1 year ago

What is the area of △FGH to the nearest tenth of a square meter? The image is of a triangle GHF with base GH length 2m, FG is 2.

Gnesinka [82]

First, we are going to use the law of cosines to find the length of the line segment FH:
$FH= \sqrt{2.5^{2}+2^{2}-(2)(2.5)Cos(121)}$
$FH= \sqrt{2.5^{2}+2^{2}-5Cos(121)}$
$FH=3.2$

Next, we are going to use the semi-perimeter formula: $s= \frac{GH+FG+FH}{2}$
$s= \frac{2+2.5+3.2}{2}$
$s= \frac{7.7}{2}$
$s=3.9$

Now that we have the semi-perimeter of our triangle, we can find its area using Heron's formula:
$A= \sqrt{s(s-GH)(s-FG)(s-FH)}$
$A= \sqrt{3.9(3.9-2)(3.9-2.5)(3.9-3.2)}$
$A= \sqrt{3.9(1.9)(1.4)(0.7)}$
$A=2.7m^{2}$

We can conclude that the area of the triangle GHF is 2.7 $m^{2}$ .

3 0

2 years ago

High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa

Misha Larkins [42]

Answer:

The correct answer is that a student have to score 1.41 standard deviations above the mean to be publicly recognized.

Step-by-step explanation:

For answering the question, we don't know the score mean of the National Financial Capability Challenge Exam and neither the population or number of students who take the exam. The only information provided is that the public recognition in this normal distribution is only for students that scores in the top 8%. In other words for students above 92% of the population.

With this information, we can go to a Z Score Table and check that for being on the top 8% (above the 92% of any population), your result must be 1.405 standard deviations above the mean.

Rounding the answer to 2 decimal places, it's 1.41 standard deviations above the mean.

7 0

2 years ago