Answer:
True options: 1, 2 and 5
Step-by-step explanation:
From the given diagram, you can see that the center of the hyperbola is placed at the origin, so first option is true (see attached diagram for definition of center, vertices, foci, i.e.)
There are two vertices of the hyperbola, they are placed at (-6,0) and (6,0), so second option is true.
The transverse axis is the segment connecting vertices, this segment is horizontal, so option 3 is false.
The foci are not placed within the rectangular reference box, so this option is false.
The directrices are vertical lines with equations 
, so this option is true.
Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Bala had 9 stickers
You could set this up as a equation. Because there was a total of 26 you would for sure put =26. Next you are told Alvin has 8 MORE than Bali, therefore you would be adding the unknown value of Bala by 8. This could be represented as x+8=26. Now that you have x added to 8 you need to add another x to the equation to fully represent the problem since Alvin has 8 more stickers than Bala does. The new equation would become 2x+8=26.
You must now isolate x by first subtraction 8 from both sides which will leave you with 2x=18. Then you divide on both sides by 2 and will leave you with x=9
Answer:
The probability of not rain during the entire festival is 0.19
Step-by-step explanation:
The Complement Rule states that the sum of the probabilities of an event and its complement must equal 1.
In this case we have the probability of raining of each day, we need the probability of NOT raining.
First day= 45% chance of rain, the complement is 55%
Second day 55% chance of rain, the complement is 45%
Third day a 10% chance of rain, the complement is 90%
Fourth day a 10% chance of rain, the complement is 90%
Fifth day 5% chance of rain, the complement is 95%
To get the probability of NOT raining in the entire festival is the multiplication of all the complements.
P(not raining) = 0.55 x 0.45 x 0.90 x 0.90 x 0.95= 0.19
