In the diagram, the length of segment TR can be represented by 5x – 4. Line n is a perpendicular bisector of line segment T V. I
t intersects line segment T V at point R. Line n also contains points Q and S. Line segment Q V is 3 x + 4. Line segment R V is 2 x + 5. Line segment T S is 6 x minus 3. What is the length of segment VS? 3 units 11 units 13 units 15 units
2 answers:
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Answer:
The graph is possible for
Step-by-step explanation:
we know that
The discriminant of a quadratic equation of the form
is equal to
If D=0 the quadratic equation has only one real solution
If D>0 the quadratic equation has two real solutions
If D<0 the quadratic equation has no real solution (complex solutions)
In this problem , looking at the graph, the quadratic equation has two real solutions (the solutions are the x-intercepts)
so
therefore
The graph is possible for