Which expression would be easier to simplify if you used the associative property to change the grouping
2 answers:
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The question is incomplete. But this explanation will help you very much.
1) Regarding the function
, its graph always passes through the points (1,0) and (a,1).
That is due to the properties of logarithm function:
a)
b)
<span>
That in turn is due to the properties of the exponential functions.
a^0 = 1 and a^1 = a
</span>
2) Regarding the y-axis.
The function will never touch the y-axis, because the logaritm of zero is not defined. So the graph lies to the righ of the y-axis (i.e. the domain of the function is x > 0)
1) Regarding the function
That is due to the properties of logarithm function:
a)
b)
<span>
That in turn is due to the properties of the exponential functions.
a^0 = 1 and a^1 = a
</span>
2) Regarding the y-axis.
The function
Period is from 0 to 2pi
take the deritivive then take it again
we get f''(x)=-4cos²(x)-2cos(x)+2
it is negative between 0 and pi/3 and also between 5pi/3 and 2pi
concave down in the interval
![[0, \frac{ \pi }{3}]](https://tex.z-dn.net/?f=%5B0%2C%20%5Cfrac%7B%20%5Cpi%20%7D%7B3%7D%5D)
U ![[\frac{ 5\pi }{3},2\pi]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%205%5Cpi%20%7D%7B3%7D%2C2%5Cpi%5D)
take the deritivive then take it again
we get f''(x)=-4cos²(x)-2cos(x)+2
it is negative between 0 and pi/3 and also between 5pi/3 and 2pi
concave down in the interval