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avanturin [10]
2 years ago
6

Mia records the distance traveled in x minutes in the table below, while Alexa uses a graph to record her distance traveled over

the same time period. Alexa’s Graph A graph has time (minutes) on the x-axis and Distance traveled (miles) on the y-axis. A line goes through points (4, 3) and (8, 6). Mia’s Table A 2-column table with 4 rows. Column 1 is labeled Time (minutes) with entries 10, 18, 20, 26. Column 2 is labeled Distance Traveled (miles) with entries 5, 9, 10, 13. Based on the data on the graph and in the table, which statement gives an accurate comparison? Alexa traveled at a faster rate because the slope of her line is Three-fourths, which is greater than the slope of the line described by the data in Mia’s table. Alexa traveled at a faster rate because the slope of her line is Four-thirds, which is greater than the slope of the line described by the data in Mia’s table. Mia traveled at a faster rate because the slope of the line described by the data in her table is One-half, which is greater than the slope of the line on Alexa’s graph. Mia traveled at a faster rate because the slope of the line described by the data in her table is StartFraction 2 Over 1 EndFraction, which is greater than the slope of the line on Alexa’s graph.
Mathematics
2 answers:
xenn [34]2 years ago
5 0

Answer:

Number 1

Step-by-step explanation:

Because she travels quicker and he line is 3/4

marysya [2.9K]2 years ago
3 0

Answer: Alexa traveled at a faster rate because the slope of her line is Three-fourths, which is greater than the slope of the line described by the data in Mia’s table.

Step-by-step explanation: On Edgenuity!!!!!!!!!

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Researchers are studying populations of two squirrels, the eastern gray and the western gray. For the eastern gray squirrel, abo
Tresset [83]

Answer:

p₁  -  p₂  = ( -0,28 . 0 )

Step-by-step explanation:

Eastern gray squirrel

Sample size    n₁  = 60

p₁  =  22 %        p₁  = 0,22       then     q₁  = 1 - 0,22      q₁ = 0,88

Western gray squirrel

Sample size  n₂  =  120

p₂ = 36%     p₂ = 0,36     Then    q₂  =  1  - 0,36     q₂  =  0,64

p (s)  = ( p₁ - p₂ ) /√ (p₁*q₁ ) / n₁   +  (p₂*q₂/ n₂)

p(s)  = ( 0,22 -  0,36 ) /√ (0,22*0,88)/60  +  ( 0,36*0,64)/120

p(s)  =  -0,14 /0,071

p(s) = - 1,9718

Then

CI = (  p₁ - p₂ ) ± p(s) *EED

EED =  /√ (p₁*q₁ ) / n₁   +  (p₂*q₂/ n₂)   = 0,071

CI = (  - 0,14  ±  1,9718 * 0,071 )

CI =  ( - 0,14  ±  0,14 )

CI =  ( - 0,28 ;  0 )

we will find with 95% of confidence the mean of the sampling distribution of the difference in sample proportion in the interval  ( -0,28 , 0 )

p₁  -  p₂  = ( -0,28 . 0 )

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2 years ago
Three different divers kept track of the number of treasure boxes they've found this year.
steposvetlana [31]
Choice a i'm pretty sure !
7 0
1 year ago
Read 2 more answers
Which part of the proof does the fourth statement and reason represent?
denis-greek [22]

Answer:

Option B is correct.

Reason:It is an argument

Step-by-step explanation:

Given: AB \cong BC  and BC \cong EF

By transitive property:  a = b  and b = c then, a =c

⇒AB \cong EF

AB = EF                                [def of \cong segment]

By Segment Addition Postulate states that given  two points A and C, and a third point B lies on the line segment AC if and only if the distances between the  points satisfy the equation

AB + BC = AC.

Since, the line segment EG , F lies on the line segment;

then, by segment addition postulates we have;

EG = EF + FG

By substitution AB=EF

⇒ EG = AB + FG                     hence proved!

Since, in the fourth statement reason is:  It is an argument

3 0
2 years ago
Find the height of a clock tower if the angle of elevation from a horizontal point 430 m from its base is 40°.
zaharov [31]

\\ \sf\longmapsto tan40=\dfrac{P}{430}

\\ \sf\longmapsto 0.83=\dfrac{P}{430}

\\ \sf\longmapsto P=430(0.83)

\\ \sf\longmapsto P\approx361m

  • P=Height of tower

5 0
2 years ago
Read 2 more answers
The parallel dotplots below display the girths (belly
liraira [26]

Answer:

The standard deviation for the distribution of girths is

about the same for both male and female pigs.

Step-by-step explanation:

Step 1

We will interprete the dotplots

For the Male pigs

24, 26, 26, 26, 26, 26, 26, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 28, 30, 30, 30, 30, 30, 30, 32

Range

Maximum value - Minimum value

= 32 - 24

= 8

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 26

7th value = 26

Q1 = 26 + 26/2

Q1 = 26

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 30

20th value = 30

Q3= 30+ 30/2

= 30

IQR = 30 - 26

= 4

Standard deviation

Mean

First we find the mean

= 24+ 26+26+ 26+ 26+ 26+26+28+ 28+ 28+ 28+28+ 28+ 28+28+ 28+28+28+30+ 30+30+ 30+30+30+32/28

= 700/25

= 28

Standard deviation Formula = √(x - mean)²/n - 1

= √[(24-28)² + (26- 28)² + (26 -28)² + (26 - 28)² +................ (32 - 28)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Female Pigs

21, 23, 23, 23,23,23,23,25, 25, 25, 25, 25, 25, 25, 25, 25, 25,25, 27, 27, 27, 27,27, 27, 29

Range:

Maximum value - Minimum value

= 29 - 21

8

IQR

IQR = Interquartile range = Q3 - Q1

Q1 formula = 1/4(n + 1)th

=n = 25

= 1/4(25 + 1)

= 1/4(26)

= 26/4

= 6.5

This mean the value is between the 6th and 7th value

6th value = 23

7th value = 23

Q1 = 23 + 23/2

Q1 = 23

Q3

Q3 formula = 3/4(n + 1)th

=n = 25

= 3/4(25 + 1)

= 3/4(26)

= 78/4

= 19.5

This mean the value is between the 19th and 20th value

19th value = 27

20th value = 27

Q3= 27+ 27/2

Q3 = 27

IQR = 27 - 23

= 4

First we find the Mean

=(21+23+23+23+23+23+23+25+ 25+ 25+ 25+25+ 25+ 25+ 25+25+25+25+27+27+ 27+27+27+ 27+29)/25

= 625/25

= 25

Standard deviation Formula = √(x - mean)²/n - 1

= √[(21-25)² + (23- 25)² + (23 -25)² + (23 - 25)² +................ (29 - 25)²]/25 - 1

= √(16 + 4 + 4+ 4+ 4+4+ 4+0+ 0+ 0+ 0+0+ 0+ 0+ 0+0+0+0+ 4+ 4+4+4+4+ 4+ 16)/25 - 1

= √80/25 - 1

=√3.333333333

1.825741858

Looking at the calculation above and comparing both the girths from the male and female

We can conclude that: The standard deviation for the distribution of girths is

about the same for both male and female pigs which is 1.825741858

5 0
2 years ago
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