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2 years ago

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The graph of y=h(x) is shown below. The function f(x) is defined by f(x) =-1/2h(x)+3. (a) What three transformations have occurr

ed to the graph of h to produce the graph of f? Specify the transformations and the order they occurred in.

1 answer:

Fudgin [204]2 years ago

3 0

Answer:

Reflection over x, Stretch by 1/2, translate up 3 units

Step-by-step explanation:

:)

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If we changed the 3 to a 0 in the equation, what would happen to the graph?

jasenka [17]

Answer:

The graph will be three units lower

Step-by-step explanation:

The graph will be three units lower

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2 years ago

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HELP!!!! 2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled fifth grade. There are 2 dots above 1, 3 above 2, 1 ab

Elis [28]

Answer:

5th grade mean - 4.67

7th grade mean - 3.46

5th-grade median - 5

7th-grade median - 3.5

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4. Given directed line segment CD, if point E divides CD three-fourths of the way from C to D, find the coordinates of E, then p

cricket20 [7]

Answer:

Point E is given by $\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )$

Step-by-step explanation:

Let points C and D be $(x_0,y_0),\,(x_1,y_1)$ and let point E divides it in ratio $m:n$ .

Then coordinates of point E are given by $\left ( \frac{mx_1+nx_0}{m+n},\frac{my_1+ny_0}{m+n} \right )$

Put $m:n=3:4$

Point E is given by $\left ( \frac{3mx_1+4x_0}{3+4},\frac{3y_1+4y_0}{3+4} \right )=\left ( \frac{3mx_1+4x_0}{7},\frac{3y_1+4y_0}{7} \right )$

Now plot point E.

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2 years ago

Jillian is selling boxes of cookies to raise money for her basketball team. The 10 oz. box costs $3.50, while the 16 oz. box cos

cluponka [151]

<span>we have to solve simultaneous equations.

x = 10 oz. boxes

y = 16 oz. boxes

simultaneous equations

x + y = 24 ---1)

3.50x + 5.00y = 97.50 ----2)

to solve for x we need to eliminate y, therefore we have to multiply 1st equation by 5

5x + 5y = 120 --3)

subtract 3) - 2)

5x - 3.50x = 120 - 97.50

1.50x = 22.5 x = 15

number of 10 oz. boxes are 15. answer is d.15</span>

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2 years ago

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It is believed that as many as 23% of adults over 50 never graduated from high school. We wish to see if this percentage is the

JulijaS [17]

Answer:

1) n=48

2) n=298

3) n=426

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\hat p$ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

Part 1

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.10$ and $\alpha/2 =0.05$ . And the critical value would be given by:

$z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.1$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume that the estimated proportion is 0.23 for the 25 to 30 group. And replacing into equation (b) the values from part a we got:

$n=\frac{0.23(1-0.23)}{(\frac{0.1}{1.64})^2}=47.63$

And rounded up we have that n=48

Part 2

The margin of error on this case changes to 0.04 so if we use the same formula but changing the value for ME we got:

$n=\frac{0.23(1-0.23)}{(\frac{0.04}{1.64})^2}=297.7$

And rounded up we have that n=298

Part 3

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume that the estimated proportion is 0.23 for the 25 to 30 group. And replacing into equation (b) the values from part a we got:

$n=\frac{0.23(1-0.23)}{(\frac{0.04}{1.96})^2}=425.22$

And rounded up we have that n=426

3 0

2 years ago