Answer:
Dependent: Cost of the ride.
Independent : Number of rides.
Step-by-step explanation:
The independent variable is the variable what we change and the dependent variable is the variables which changes because of that changes.
Here the total cost of ride changes for any change in the number of rides.
Hence, the number of rides is the independent variable and the total cost of ride is the dependent variable
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
2.) RS≅RS | Reflexive Property
3.) △RST ≅ △RSQ | AAS Triangle Congruence Property
Answer:

Step-by-step explanation:

A(4,2), B(2,8)
AC: y=x-2
Point point form for a line through (a,b) and (c,d) is (c-a)(y-b)=(d-b)(x-a)
AB is (2 - 4)(y - 2) = (8-2)(x-4)
-2(y - 2)=6(x-4)
y - 2 = -3(x-4)
y = -3x + 14
BC is perpendicular through B, so slope 1/3 and we calculate the constant as y-(1/3)x:
y = (1/3) x + (8 - (1/3)(2) ) = (1/3) x + 22/3
a)Answer: BC is y = (1/3) x + 22/3
C is the meet of AC and BC,
x - 2 = (1/3) x + 22/3
3x - 6 = x + 22
2x = 28
x = 14
y = x-2 = 12
Check: y = (1/3)x + 22/3 = (14+22)/3 = 36/3 = 12 good
C(14,12)
The remaining corner is D. We have A-B=D-C or
D = A+C-B+C = (4,2)+(14,12)-(2,8) = (16, 6)
b)Answer: B(2,8) [given, but asked for] C(14,12), D(16,6)
Answer:
The cost is $9.70 per kilogram.
Step-by-step explanation:
This can be solved by a rule of three.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.
Solution:
The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:
1 pound - xkg
2.2 pound - 1 kg


kg
Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?
$4.40 - 0.45kg
$x - 1kg



The cost is $9.70 per kilogram.