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2 years ago

5

A lion runs 45 mph and crosses a bridge in 40 seconds. A cheetah runs across the same bridge in 30 seconds. How fast does the ch

eetah run?

1 answer:

Aleks04 [339]2 years ago

7 0

Answer:

60 mph because the cheetah runs at 4/3 of the lion's pace, which is 45 mph. 4/3 x 45 is 60.

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What is Question I (if m<EBF = 117°, fine m<ABE)

Natasha_Volkova [10]

Answer:

m∠ABE = 27°

Step-by-step explanation:

* Lets look to the figure to solve the problem

- AC is a line

- Ray BF intersects the line AC at B

- Ray BF ⊥ line AC

∴ ∠ABF and ∠CBF are right angles

∴ m∠ABF = m∠CBF = 90°

- Rays BE and BD intersect the line AC at B

∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure

∴ BE is the bisector of angle ABD

∵ m∠EBF = 117°

∵ m∠EBF = m∠ABE + m∠ABF

∵ m∠ABF = 90°

∴ 117° = m∠ABE + 90°

- Subtract 90 from both sides

∴ m∠ABE = 27°

4 0

2 years ago

Read 2 more answers

If a baseball player hits a baseball from 4 feet off the ground with an initial velocity of 64 feet per second, how long will it

topjm [15]

Answer:

0.64 seconds

Step-by-step explanation:

In the equation provided:

h = −16t2 + 4t + 4

h is the height of the ball and t is time. Since we want to find the time when the ball touches the floor, then height is 0. This leaves us with the equation

-16 $t^{2}$ + 4t + 4 = 0

This is a quadratic equation can be solved with the following formula:

$x= \frac{-b+-\sqrt{b^{2}-4ac } }{2a}$

where a=-16

b=4

c=4

Solving for t we will find two different results:

$t1=\frac{-4-\sqrt{272} }{2(-16)} =0.125+0.125\sqrt{17} =0.64039$ $t2=\frac{-4+\sqrt{272} }{2(-16)} =0.125-0.125\sqrt{17} =-0.39039$

Since time can't be negative, we discard t2 and choose t1.

Since it is required to answer in the nearest hundredth, we round the result to t=0.64 seconds.

5 0

1 year ago

Alannah has two lengths of ribbon.

ankoles [38]

Answer:

Longest possible length for each of the shorter lengths of ribbon is 9 cm because greatest common factor for both 36 and 45 is 9.

Step-by-step explanation:

Alannah has two ribbons one length is 36cm and other is 45cm.

It asked to find shorter length of ribbons that each cut into equal pieces with out no ribbon left over.

So, let's find greatest common factor for both 36 and 45.

Let's prime factor each number

36= 2*2*3*3

45= 3*3*5

So, GCF is product of common factors for both numbers.

GCF= 3*3 =9

So, longest possible length for each of the shorter lengths of ribbon is 9 cm.

Learn more about GCF in brainly.com/question/21612147.

7 0

1 year ago

Quadrilaterals WXYZ and BADC are congruent. In addition, WX ≅ DC and XY ≅ BC. If AD = 4 cm and AB = 6 cm, what is the perimeter

Yanka [14]

If <u>quadrilaterals</u> WXYZ and BADC are <u>congruent</u>, then their corresponding <u>sides</u> are congruent.

Given that

WX≅DC,
XY≅BC,

you can state that

YZ≅AB,
WZ≅AD.

If AD = 4 cm and AB = 6 cm, then WZ = 4 cm and YZ = 6 cm. Opposite rectangle sides are congruent, then XY = 4 cm and WX = 6 cm.

The perimeter of WXYZ is

P = WX + XY + YZ + WZ = 6 + 4 + 6 + 4 = 20 cm.

Answer: 20 cm

6 0

2 years ago

Read 2 more answers

A 12-centimeter rod is held between a flashlight and a wall as shown. Find the length of the shadow on

choli [55]

Answer:

48 cm

Step-by-step explanation:

Given:

Distance of rod from the wall = 45 cm

Distance of rod from the light = 15 cm

Length of rod = 12 cm

We can see that <DAM and <BAF are equal

Also, <DMA and <BFM are equal because they are corresponding angles

To find the length of the shadow, let's take the equation

$\frac{DM}{BF} = \frac{AM}{A.F}$

Where.:

DM = ½ of length of the rod = ½*12 = 6

A.F = 15 + 45 = 60 cm

AM = 15 cm

Therefore,

$\frac{DM}{BF} = \frac{AM}{A.F}$

$= \frac{6}{BF} = \frac{15}{60}$

Cross multiplying, we have:

15 * B.F = 60 * 6

15 * B.F = 360

$BF = \frac{360}{15}$

BF = 24 cm

The shadow on the wall =

2 * BF

= 2 * 24

= 48 cm

The shadow on the wall is 48 cm

7 0

1 year ago