I took a picture of the answer for you.
Answer:
(A)EF corresponds to E'F'
(C)∠EDG Is-congruent-to ∠E'D'G'
(D)∠DEF Is-congruent-to ∠D'E'F'
(F)The transformation is a rigid transformation.
Step-by-step explanation:
Given:
- Parallelogram DEFG is mapped to D'E'F'G'
- DEFG and D'E'F'G' have identical side lengths and angle measures.
The following applies:
- EF corresponds to E'F'
- ∠EDG Is-congruent-to ∠E'D'G'
- ∠DEF Is-congruent-to ∠D'E'F'
Now, a rigid transformation is a transformation of the plane that preserves length. Since the two parallelograms have identical side lengths:
- The transformation is a rigid transformation.
Note that a reflection is an isometric transformation. Therefore the statement "The transformation is not isometric" is INCORRECT.
FG and GD are adjacent sides, therefore they may not necessarily be congruent. Thus FG does not corresponds to G'D'
