The area of a square is expressed as the length of the side to the power of two, A = s^2. We were given the area of the enlarged photo which is 256 in^2. Also, it was stated that the length of the enlarged photo is the length of the original photo plus ten inches. So, from these statements we can make an equation to solve for x which represents the length of the original photo.
A = s^2
where s = (x+10)
A = (x+10)^2 = 256
Solving for x,
x= 6 in.
The dimensions of the original photo is 6 x 6.
360 - 250 = 110
m<1 = 110/2 = 55
answer
55
You would be able to hire 40. Hope this helps
Add some of them or all of them to your sum of 47.75, if either or exceeds the limit then that is what left out.
Answer:
9.48*
Step-by-step explanation:
This is a right triangle. The formula for solving the Hypotenuse, or the longest side of the right triangle is A^2 + B^2 = C^2. If we put the numbers from the problem into the formula this is what we get :
3^2 + 9^2 = C^2
9 + 81 = C^2
90 = C^2
9.48 = C
* This is rounded, the exact number is closer to 9.486832980505138. Your class should tell you what to round to.
