<span>George will have enough money in 3 years. This is because at 5 percent interest per year, in one year he will have $23,100. In two years, he will have $24,155. In 3 years he will have $25,362.75 which will put him slightly over his goal of a 20% down payment.</span>
1) You included neihter what Ramesh says nor the statements, then I can you tell some facts about the pattern.
2) The sequence is: 2401, 343, 49, 7, and 1.
3) The first term is 2401
4) The sequence is a decreasing geometric one.
5) The ratio is found dividing two consecutive terms (the second by the first, or the third by the second, or the fourth by the third, or the fifth by fourth):
1/7 = 7 / 49 = 49 / 343 = 343 / 2401.
So, the ratio is 1/7
6) The sum of that sequence is 2401 + 343 + 49 + 7 + 1 = 2801
Answer:
Step-by-step explanation:
We would apply the formula for exponential decay which is expressed as
A = P(1 - r/n)^ nt
Where
A represents the value after t years.
n represents the period for which the decrease in value is calculated
t represents the number of years.
P represents the value population.
r represents rate of decrease.
From the information given,
P = 23000
r = 8% = 8/100 = 0.08
n = 1
Therefore, the exponential decay function described in this situation is
A = 23000(1 - 0.08/n)1)^ 1 × t
A = 23000(0.92)^t
If A = 15000, then
15000 = 23000(0.92)^t
0.92^t = 15000/23000 = 0.6522
Taking log of both sides to base 10
Log 0.92^t = log 0.6522
tlog 0.92 = log 0.6522
- 0.036t = - 0.1856
t = - 0.1856/- 0.036
t = 5 years to the nearest year
Answer:
(–5, 12) is the correct answer.
Step-by-step explanation:
We are given the following values:
Now, we know the following identities:
Now, the values are:
Sine value is positive and cos, tan values are negative.
It can be clearly observed that 
is in 2nd quadrant.
2nd quadrant means, the value of 
will be negative and 
will be positive.
Let us have a look at the value of 
:
Please refer to the attached image for clear understanding and detailed explanation.
Hence, the correct answer is coordinate (x,y) is (–5, 12)
The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is
for the mean chart
uclim= x+A2xR
where x = sum(of the value) / number of each value
and for
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin
in the case of the sample 1: S1
the data are:
79.2 78.8 80.0 78.4 81.0
the mean is x1 = (</span>79.2 + 78.8 + 80.0 + 78.4 + 81.0) / 5= 79.48
<span>its range is R 1= 81.0 -78.4 = 2.6
we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14 , R2=2.3
</span>S3: x3= 80.14 , R3=1.2
S4: x4= 79.60 , R4=1.7
S5: x5= 80.02 , R5=2.0
S6: x6=80.38 , R6=1.4
<span>
therefore the average value is X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95 and lclim is always equal to 0, because D3=0
we can say that the process is not in control.
</span>
