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Serhud [2]
1 year ago
12

a square with an area of 1 square meter is decomposed into 9 identical small squares. Each small square is decomposed into two i

dentical triangles. what is the area in square meters of 6 triangles
Mathematics
1 answer:
Papessa [141]1 year ago
5 0

Area of one big square = 1 square meter

Now the bigger square is divided into 9 smaller square

Area of 9 small squares = Area of 1 big square= 1 square meter

So applying unitary method we can find are of 1 small square.

Area of 1 small square = 1/9 square meter

Now each small square is divided into two identical triangles.

So ,

Area of 1 triangle = 1/2 of area of 1 small square =(1/2) (1/9) = 1/18 square meter

Again applying unitary method to find area of 6 triangles,

Area of 6 triangles = 6 * area of 1 triangle = 6 * (1/18) = 1/3 square meter

Answer : Area of 6 triangles is 1/3 square meters.



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2 years ago
A side of a regular six - sided polygon is 8cm long. The perimeter of a similar polygon is 60cm. What is the length of a side of
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Answer:

  10 cm

Step-by-step explanation:

The larger polygon is also a regular 6-sided polygon, so each side is 1/6 of the perimeter length:

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2 years ago
The surface areas of two similar solids are 312 ft2 and 1,198 ft2. The volume of the smaller solid is 239 ft3. What is the volum
marin [14]

Answer:

The volume of the larger solid is 1,798\ ft^{3}

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar , then the ratio of its surface areas is equal to the scale factor squared

so

Let

z-------> the scale factor

x-------------> surface area larger solid

y-------------> surface area smaller solid

z^{2} =\frac{x}{y}

substitute

z^{2} =\frac{1,198}{312}

z=\sqrt{\frac{1,198}{312}} ----> scale factor

step 2

Find the volume of the larger solid

we know that

If two figures are similar , then the ratio of its volumes is equal to the scale factor elevated to the cube

so

Let

z-------> the scale factor

x-------------> volume of the  larger solid

y-------------> volume of the smaller solid

z^{3}=\frac{x}{y}

we have

z=\sqrt{\frac{1,198}{312}}

y=239\ ft^{3}

substitute the values

(\sqrt{\frac{1,198}{312}}^{3})=\frac{x}{239}

x=239*(\sqrt{\frac{1,198}{312}}^{3})=1,798\ ft^{3}

5 0
1 year ago
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The graph shows the amount of dirt left to remove, y, with respect to number of loads of dirt, x. Use the graph to complete each
Tema [17]

Part 1. When x=0, then y=900 (from the graph). This means that y-intercept is at point (0,900).

Answer Part 1: 900

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Answer Part 2: the total amount of dirt to remove.

7 0
1 year ago
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Given that the two parallel lines are cut by a transversal, and the measure of angle 2 is 50 degrees. Find each of the missing a
Mandarinka [93]

Answer:

Step-by-step explanation:

Lines m and l are the parallel lines and a line 'n' is a transverse intersecting these lines.

m∠2 = 50°

m∠1 + m∠2 = 180° [Linear pair of angles]

m∠1 = 180° - 50°

m∠1 = 130°

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m∠3 + m∠5 = 180° [Consecutive interior angles]

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m∠6 + m∠5 = 180° [Linear pair of angles]

m∠6 = 180° - 50° = 130°

7 0
1 year ago
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