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yuradex [85]
2 years ago
15

I borrowed 12000 rupees from jamshed at 6 percent per annum simple interest for 2 years .Had i borrwed this sum at 6 percent per

annum compound interest, what extra amount would i gave to pay ?
Mathematics
1 answer:
Leni [432]2 years ago
6 0

Answer:

43.2 Rupees

Step-by-step explanation:

To determine how much extra will be paid, we calculate the Amount at Simple Interest and the Amount at Compound Interest and Make Comparisons.

Now, Principal=12000

Rate=6%

Time= 2 years

Amount at Simple Interest= Principal+ Simple Interest

=P+(PRT)/100

=12000+(12000X6X2)/100

=12000+1440

=13440 Indian Rupees

Amount at Compound Interest

A=P(1+r)ⁿ

=12000(1+0.06)²

=12000(1.06)²

=13483.2 Indian Rupees

Difference=Amount at Compound Interest- Amount at Simple Interest

=13483.2-13440

=43.2 Indian Rupees

If he had borrowed at Compound interest, he would have paid an extra 43.2 Rupees

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Prove the following using a proof by contradiction:The average of four real numbers is greater than or equal to at least one of
skelet666 [1.2K]

Answer:

By contradiction it can be proved that:

Average of four real numbers will be greater than or equal to at least one of the four real numbers.

Step-by-step explanation:

Method of contradiction means we assume opposite to the facts to be proved and then we contradict our assumption.

As a result, we prove the fact.

Here, let the four number be:

p, q, r, s

The average will be Sum of all numbers divided by count of numbers.

\dfrac{p+ q+ r+ s}4

Now, let us assume the opposite that the average is less than all the numbers.

i.e.

\dfrac{p+ q+ r+ s}4

\dfrac{p+ q+ r+ s}4

Now, let us add all of them:

\dfrac{p+ q+ r+ s}4 +\dfrac{p+ q+ r+ s}4 +\dfrac{p+ q+ r+ s}4 +\dfrac{p+ q+ r+ s}4  < p+q+r+s\\\Rightarrow \dfrac{4(p+q+r+s)}4

Which can never be possible hence, our assumption is contradicted.

our assumption is wrong.

Therefore, by contradiction it is proved that:

Average of four real numbers will be greater than or equal to at least one of the four real numbers.

8 0
2 years ago
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. g(x) = 7x u2 − 1 u2 + 1 du 6x Hint: 7x
VikaD [51]

It looks like you're given

g(x)=\displaystyle\int_{6x}^{7x}\frac{u^2-1}{u^2+1}\,\mathrm du

Then by the additivity of definite integrals this is the same as

g(x)=\displaystyle\int_0^{7x}\frac{u^2-1}{u^2+1}\,\mathrm du-\int_0^{6x}\frac{u^2-1}{u^2+1}\,\mathrm du

(presumably this is what the hint suggests to use)

Then by the fundamental theorem of calculus, we have

\dfrac{\mathrm dg}{\mathrm dx}=7\dfrac{(7x)^2-1}{(7x)^2+1}-6\dfrac{(6x)^2-1}{(6x)^2+1}=\dfrac{1764x^4+169x^2-1}{1764x^4+85x^2+1}

8 0
2 years ago
Triangles E F G and E prime F prime G prime are shown. Angles F E G and F prime E prime G prime are 72 degrees. Angles E F G and
Karolina [17]

Answer:

We need a non-included side of one triangle

Step-by-step explanation:

By means of the AAS postulate.

The Angle-Angle-Side postulate (AAS) tells us that if two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of another triangle, then the two triangles are congruent.

3 0
2 years ago
Without properly working spark plugs, a vehicle will not run. For a specific vehicle, the spark plugs are supposed to have a gap
Salsk061 [2.6K]

Answer:

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3)  = 0.9922</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the mean of the Normal distribution = 4.1mm</em>

<em>Given that the standard deviation of the Normal distribution = 0.0075mm</em>

<em>Let 'X' be the random variable in a normal distribution</em>

Given that X₁ = 3.9mm

Z_{1} = \frac{X_{1} -mean}{S.D}

Z_{1} = \frac{3.9 -4.1}{0.075} =  -2.666

Given that X₂ = 4.3mm

Z_{2} = \frac{X_{2} -mean}{S.D}

Z_{1} = \frac{4.3 -4.1}{0.075} =  2.666

<u><em>Step(ii):-</em></u>

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3) = P(-2.666≤Z≤2.666)</em>

<em>                      = P(Z≤2.666)-P(Z≤-2.666)</em>

<em>                     = 0.5 +A(2.666) - (0.5-A(2.666)</em>

<em>                    = 2 × A(2.666)</em>

<em>                  = 2×0.4961</em>

<em>                  = 0.9922</em>

<u><em>Final answer:-</em></u>

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3)  = 0.9922</em>

<em></em>

3 0
1 year ago
Which ordered pairs in the form (x, y) are solutions to the equation 3x – 4y = 21? Choose all answers that are correct.
bekas [8.4K]
A. (−3, 3)
<span>3x – 4y = 21
</span>3(-3) - 4(3) = 21
-21 = 21 >>>>> not equal

B. (−1, −6)
<span>3(-1) - 4(-6) = 21
</span>21 = 21 >>>>>>>>>>Equal

C. (7, 0)
<span>3(7) - 4(0) = 21
</span>21 = 21>>>>>>>>>>equal

D. (11, 3)
<span>3(11) - 4(3) = 21
</span>21 = 21 >>>>>>>>>equal
5 0
2 years ago
Read 2 more answers
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