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2 years ago

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Triangles E F G and E prime F prime G prime are shown. Angles F E G and F prime E prime G prime are 72 degrees. Angles E F G and

E prime F prime G prime are 66 degrees. What additional information could be used to prove ΔEFG ΔE'F'G' using AAS? Check all that apply.

1 answer:

Karolina [17]2 years ago

3 0

Answer:

We need a non-included side of one triangle

Step-by-step explanation:

By means of the AAS postulate.

The Angle-Angle-Side postulate (AAS) tells us that if two angles and a non-included side of one triangle are congruent to two angles and the corresponding non-included side of another triangle, then the two triangles are congruent.

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There are 12 boys and 16 girls in a classroom. which represents the simplified ratio of girls to students in the classroom?

Papessa [141]

The unsimplified version is 12:16
you have to find the highest common factor in them
in this case it would be 4
divide both numbers by 4
3:4

hope this helps you

3 0

2 years ago

Read 2 more answers

The solutions to a quadratic equation are x = 2 and x = 7. If k is a nonzero constant, which of the following must be equal to t

Serggg [28]

ANSWER

The correct option is,
$k(x - 2)(x - 7) = 0$

EXPLANATION

We were given that the solutions of the quadratic equation are
$x = 2$
and
$x = 7.$

This tells us that,

$x - 2$

and
$x - 7$

are factors of the quadratic equation.

This implies that the quadratic equation is of the form,

$(x - 2)(x - 7) = 0$

We were also told that

$k$

is a non zero constant.

This means that we can use k to multiply the whole equation and the solution will not be affected.

Our equation now becomes,

$k(x - 2)(x - 7) = 0$

Hence the correct answer is A.

5 0

2 years ago

Read 2 more answers

Jerry's Fish Shack claims that 16% of its employees are late to work once a week. The manager surveyed 25 employees and found th

larisa86 [58]

Answer:

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

$p_v =2*P(z>0.546)=0.585$

Step-by-step explanation:

Data given and notation

n=25 represent the random sample taken

$\hat p=0.2$ estimated proportion

$p_o=0.16$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of employess are late to work is 0.16, so we need to apply a one sample proportion test:

Null hypothesis: $p=0.16$

Alternative hypothesis: $p \neq 0.16$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.20 -0.16}{\sqrt{\frac{0.16(1-0.16)}{25}}}=0.546$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>0.546)=0.585$

4 0

2 years ago

Write v as a linear combination of u1, u2, and u3, if possible. (If not possible, enter IMPOSSIBLE.) v = (7, −14, −3, −4), u1 =

AlexFokin [52]

Answer:

IMPOSSIBLE

Step-by-step explanation:

8 0

2 years ago

The coordinate values of the vertices of △klm are integers. triangle klm has vertices located at (1, 1), (5, 4) and (5, 1). whic

worty [1.4K]

The rest of the queastion is :
<span> A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================
</span>

<span>The distance between two points (x₁,y₁),(x₂,y₂) = d
$d = \sqrt{ (x2-x1)^{2} + (y2-y1)^{2} }$ </span>

we have <span>K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = </span><span> $d = \sqrt{ (5-1)^{2} + (4-1)^{2} }$ = 5
</span>LM = <span> $d = \sqrt{ (5-5)^{2} + (1-4)^{2} }$ = 3
KM = </span><span> $d = \sqrt{ (5-1)^{2} + (1-1)^{2} }$ = 4

now check each group from the choices
the group that will give the same result will be the correct choice.
</span>The correct choice is C
<span>C) (-1, 1), (-4, 5), (-1, 5)

check the answer;
</span><span>K'(-1, 1), L'(-4, 5), M'(-1, 5)
</span>
<span>K'L' = <span> $d = \sqrt{ (-4+1)^{2} + (5-1)^{2} }$ = 5
</span>L'M' = <span> $d = \sqrt{ (-1+4)^{2} + (5-5)^{2} }$ = 3
K'M' = </span><span> $d = \sqrt{ (-1+1)^{2} + (5-1)^{2} }$ = 4</span></span>

6 0

2 years ago