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Llana [10]
2 years ago
10

1,352 pounds is what fraction of a short ton

Mathematics
1 answer:
GaryK [48]2 years ago
6 0
1 short ton = 2000 lbs

(1352 lbs)*(1 short ton)/(2000 lbs) = <em><u>0.676 short tons</u></em><u><em /></u><em><u /></em>
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Which statement best describes how to determine whether f(x) = 9 – 4x2 is an odd function? Determine whether 9 – 4(–x)2 is equiv
katovenus [111]

We have a property for odd functions, which is given below. Let f(x) be an odd function then it must satisfy the below - mentioned property.

f(-x)= -f(x)

Now, we have been given the function f(x)=9-4x^2

For this function to be odd, it must satisfy the above written property.

Replace x with -x, we get

f(-x)=9-4(-x)^2

And, we have to also find

-f(x)=-(9-4x^2)

Hence, in order to the given function to be an odd function, we must determine whether 9-4(-x)^2 is equivalent to -(9-4x^2) or not.

Therefore, C is the correct option.

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1 year ago
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HELP!! Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Rashid [163]

Answer:

20

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If S(n) is the function of exponential growth, then it can be represented as

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If b = 1.85, we can represent it as b = 1 + 0.85. Thus, the hourly percent growth rate of the bacteria would be 0.85=85%.

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Find the coordinates of the point whose ordinate is -7 and lies on y axis​
Alika [10]

Answer:

(0,-7)

Step-by-step explanation:

If nay point is form (x,y)

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given that ordinate is -7. it means that value of y coordinate is -7

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2 years ago
Angles BAE and FAC are straight angles. What angle relationship best describes angles BAC and DAC?
vova2212 [387]

Answer:

They are adjacent angles

Step-by-step explanation:

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2 years ago
Compare the process of solving |x – 1| + 1 &lt; 15 to that of solving |x – 1| + 1 &gt; 15.
kicyunya [14]
In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.

In the second case we'd also subtract 1 from both sides, and would obtain
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What would the graphs look like?

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In the second case, x has to be greater than 15 or less than -13.  Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right.  None of the values in between are solutions.

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