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2 years ago

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Joe goes to the store with $15 to buy salad. Bags of pre-washed salad on sale for $2 each. What are the possible numbers of bags

joe can buy?

1 answer:

MA_775_DIABLO [31]2 years ago

3 0

Answer:

7

Step-by-step explanation:

15/2= 7.5

he can't buy a half bag so it's 7 bags

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Bo paid bills with 1/2 of his paycheck snd put 1/5 of the remainder in savings. The rest of his paycheck he divided equally amon

frutty [35]

1/2 + 1/5(1/2) = 1/2 + 1/10 = 5/10 + 1/10 = 6/10....this leaves 4/10 (reduces to 2/5) for his children.

(2/5) / 3 = 2/5 * 1/3 = 2/15 for each child <== A

400 in each childs account.....thats (400 * 3) = 1200 ...
2/5 of what is 1200 =
2/5x = 1200
x = 1200 * 5/2
x = 6000/2
x = 3000 <== B

check...
total pay is 3000
1/2 for bills.....- 1500
1/5(-1500) = -1500/5 = -300 ....for savings
3000 - (1500 + 300) = 3000 - 1800 = 1200...remaining for the children
1200/3 = 400 ...for each child.

so ur answers are :
A. 2/15 in each childs account
B. original paycheck = $ 3000

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2 years ago

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What is the greatest counting number that divides 17, 25 and 41 and leaves the same remainder in each case?

Stels [109]

The greatest counting number that divides 17, 25 and 41 and leaves the same remainder in each case is 8

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2 years ago

good job on increasing our team sales from 90 to 130 units per day.” wow i never thought that we could increase our sales by

artcher [175]

The sales was increased by 44.4%.

Step-by-step explanation:

Lets do this cumulative
90 of 10 % = 9 which is 99
90 of 10 % = 9 which is 108
90 of 10% = 9 which is 117
90 of 10% = 9 which is 126
90 of 4 % = 3.6 which is 129.6
90 of 0.044% = 0.0396 which is 129.99
This comes to nearly 44.44 to be closer there was an increase.
Always rule 1 approximation use 50% of 90 if it is above 130.
Down it to 40% of 90 see if the sales is lower than 130.
It should always start with 50,40,30....10 percents.
Alternative should be 10,1 or decimals.
Approximation using decimals rounding up becomes simple.

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2 years ago

Which is the equation of a parabola with vertex (0, 0), that opens to the left and has a focal width of 12?

sattari [20]

Answer:

$\text{Equation of parabola is }y^2=-12x$

Step-by-step explanation:

We need to find the equation of parabola using given information

Vertex: (0,0)
Open to the left
Focal width = 12

If parabola open left and passes through origin then equation is

$y^2=-4ax$

Focal width = 12

Focal width passes through focus and focus is mid point of focal width.

Focus of above parabola would be (-a,0)

Passing point on parabola (-a,6) and (-a,-6)

Now we put passing point into equation and solve for a

$6^2=-4a(-a)$

$a=\pm 3$

a can't be negative.

Therefore, a=3

Focus: (-3,0)

Equation of parabola:

$y^2=-12x$

Please see the attachment of parabola.

$\text{Thus, Equation of parabola is }y^2=-12x$

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2 years ago

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The average length of time that three lawn-service mowers operate on a given day is 930 minutes. None of the mowers operates for

Zielflug [23.3K]

Answer:

The answer is <u>A. 990.</u>

Step-by-step explanation:

Now, to find the greatest possible length of time any of the mowers operates.

The 3 lawn-service mowers operate at the average length of time = 930 minutes.

So, the total length of time the 3 lawn mowers take = $930\times 30=2790\ minutes.$

The least length a mowers operates = 900 minutes.

Now, to find the greatest possible length of time any of the mowers operates:

Let $x$ be the greatest possible length of time any of the mowers operates.

<em>As, any one of the mowers operates greatest length.</em>

<em>So, rest of the two mowers be least at length.</em>

According to question:

$x+900+900=2790$

$x+1800=2790$

<em>Subtracting both sides by 1800 we get:</em>

$x=2790-1800$

$x=990.$

<u><em>Thus, the greatest possible length of time any of the mowers operates is 990 minutes.</em></u>

Therefore, the answer is A. 990.

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2 years ago