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2 years ago

5

give real-world examples of 2 similar situations in which one is a proportional relationship and the second one is nonproportion

al please

2 answers:

jeyben [28]2 years ago

8 0

Answer:

Proportional: (ben starts with $0) Every week, Ben gets $10 for his allowance.

Non proportional: Ben's father gives him $100. Every week, Ben gets $10 for his allowance

Step-by-step explanation:

Guest1 year ago

0 0

idk solve it

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A study is being conducted in which the health of two independent groups of ten policyholders is being monitored over a one-year

uysha [10]

Answer:

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that $p = 0.8$ .

10 students, so $n = 10$

We have to find:

$P(X \geq 9) = P(X = 9) + P(X = 10)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684$

$P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074$

$P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758$

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that $p = 0.3758$

Two groups, so $n = 2$

We have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691$

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

5 0

2 years ago

Read 2 more answers

X1/3y1/6 rewrite expression in radical form

arsen [322]

Answer:

Step-by-step explanation:

Please, use the symbol " ^ " to denote exponentiation:

x^(1/3) * y^(1/6)

In radical form, this would be:

∛x*(6th root of y) (the index of the second root is 6).

Alternatively, you could write:

∛x * √((∛y)).

8 0

2 years ago

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What is the common difference between successive terms in the sequence? 0.36, 0.26, 0.16, 0.06, –0.04, –0.14,

TiliK225 [7]

0.10
is the answer for that

5 1

2 years ago

Every week a technician in a lab needs to test the scales in the lab to make sure that they are accurate. She uses a standard ma

melisa1 [442]

Precision is a measure of how close a value is to the ideal value. In this case, we calculate the difference to know what is the closest to 4 g:

4.05 – 4 = 0.05

3.98 – 4 = -0.02

4.021 – 4 = 0.021

We can see that the value of 3.98g has the lowest difference and is therefore the closest to 4g. Hence the most precise is:

<span>3.98 g</span>

3 0

2 years ago

. Given f(x) = e 2x e 2x + 3e x + 2 : (a) Make the substitution u = e x to convert Z f(x) dx into an integral in u (HINT: The ea

MrRa [10]

Answer:

Step-by-step explanation:

Given;

$f(x)=\frac{e^{2x}}{e^{2x}+3e^x+2}$

a)

substitute $u=e^x\\du=e^x dx\\\\\int\frac{e^{2x}}{e^{2x}+3e^x+2}dx=\int\frac{e^x\dot e^x}{e^x^{2x}+3e^x+2}dx\\\\=\int\frac{udu}{u^2+3u+2}$

b)

Apply partial fraction in (a), we get;

$\frac{u}{u^2+3u+2}=\frac{2}{u+2}-\frac{1}{u+1}\\\\\therefore u^2+3u+2\\=u^2+2u+u+2\\=u(u+2)+1(u+1)\\=(u+2)(u+1)\\\\Now\,\int\frac{u}{u^2+3u+2}\,du=\int\frac{2}{u+2}du-\int\frac{1}{u+1}du\\\\=2ln|u+2|-ln|u+1|+c\\=2ln|e^x+2|-lm|e^x+1|+c$

where C is an arbitrary constant

8 0

2 years ago