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OlgaM077 [116]
2 years ago
7

What is an array of 4 x 875

Mathematics
1 answer:
OLEGan [10]2 years ago
5 0
4 rows and 875 columns, or 875 rows and 4 columns
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Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi
Romashka [77]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

6 0
2 years ago
Suppose you are considering making an investment. You have a chance to make an investment that will return either $50,000 or $10
timurjin [86]

Answer:

D because its rounded to the nearest ten

8 0
2 years ago
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The battery life for Bruhier's cell phone is longer when he has fewer apps running. When only one app is running, the battery wi
trapecia [35]

Answer:inverse, 16, 2

Step-by-step explanation:

8 0
2 years ago
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For the given cost function C(x), find the oblique asymptote of the average cost function C(X), C(x)=14,000+94x+0.03x^2
marusya05 [52]
Answer: y = 0.03x + 94

--------------------------------------

Explanation:

Lets define A(x) to be the average cost function where 
A(x) = C(x)/x
basically you divide the given cost function C(x) by the number of units produced (x)

Dividing C(x) over x leads to:
A(x) = C(x)/x
A(x) = (14000+94x+0.03x^2)/x ... substitution
A(x) = (0.03x^2+94x+14000)/x ... rearrange terms
A(x) = (0.03x^2)/x+(94x)/x+(14000)/x ... break up the fraction
A(x) = 0.03x + 94 + (14000/x) ... simplify

If x were to head off to infinity, then the portion 14000/x approaches 0. 

So this is why the oblique asymptote is y = 0.03x + 94

Basically, in the long run, the average cost will approach y = 0.03x + 94

5 0
2 years ago
Ali and Felicia analyzed the patterns of equivalent ratios for StartFraction 3 Over 8 EndFraction in the table below.
Romashka [77]

Answer:

its a

Step-by-step explanation:

6 0
2 years ago
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