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2 years ago

Find the total cost to the nearest cent $43 dinner 18% gratuity

Mathematics

1 answer:

Norma-Jean [14]2 years ago

5 0

43*1.18=$50.74
You pay 100% plus 18% tip

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Cathy has a nickel, a dime, and a quarter in her purse. She randomly picks a coin, replaces it, and then picks another coin. The

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2 years ago

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Is 14 quarter inches the most common measurement

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^ if you're talking universally, no it would be cm. But no one really says "quarter inches". You would just say inches

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2 years ago

The following data represent the number of grams of fat in breakfast meals offered at a local fast food restaurant. (a) Constru

rewona [7]

Answer:

The following are the answer to this question:

Step-by-step explanation:

In the question some data is missing, which is defined in the attached file please find it.

The table for point a:

plot for the Stem-and-leaf:

0 3 4 5 7 4

1 2 2 4 4 5 7 7 7

2 0 3 4 4 5 8 6

3 3 4 7 9 4

4 1

In point b:

Its distributed skewed is correct because in its points 1 is a tail on its right side.

please find the attached file.

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2 years ago

You are playing a board game with a friend. She owns and has developed the tiles Green Gardens and Silver Sidewalks. If you roll

IgorC [24]

Answer:

The expected value can be calculated as:

Es = x₁*p₁ + x₂*p2 + .....

where xₙ is the event (the amount of money that you win or lose, and pₙ is the probability for the event)

for example, in a 10 side dice, the probability of obtaining a specific number is 1/10.

we have a d10 i guess (a dice with 10 sides, 1 to 10)

if you roll from 1 to 7, nothing happens.

If you roll an 8, you lose $1500

if you roll a 9, you lose $75

if you roll a 10, you lose $2000 (and the game)

the expected value is,

Es = 1/10*(7*0 - 1*$1500 - 1*$75 - 1*$2000) = -$357

in the second case, you start paying $500.

if you roll a 7, you must pay $1000, if else, nothing happens.

Then the expected value is

Es = -$500 - 1/10*(-1*$1000 + 9*$0) = -$600

So the expected value is smaller in this case, so the deal is not fair

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2 years ago

Suppose that the IQs of universityâ€‹ A's students can be described by a normal model with mean 140 and standard deviation 8 poi

AnnZ [28]

Answer:

0.0266, 0.9997,0.7856

Step-by-step explanation:

Given that the IQs of universityâ€‹ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.

A) $P(X>135) = \\P(Z>0.625)\\=0.0266$

B) Since X and Y are independent we have

X-Y is Normal with mean = 140-120 =20 and $Var (x-y)=Var(x)+Var(y) = 19$

$P(X-Y)>5\\\\=1-0.00029\\=0.9997$

C) For a group of 3, average has std deviation = $\frac{11}{\sqrt{3} } \\=6.351$

$P(\bar y >115)\\= P(z>\frac{-5}{6.351} \\=0.7856$

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2 years ago