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Anastasy [175]
2 years ago
8

2. In the product of (4a3 + 5a2 – 11a) and (-15 + 3a – 7a2), the co-efficient of a4 is …………………… .

Mathematics
2 answers:
Bas_tet [7]2 years ago
8 0

The only pairs that will give you some multiple of a^4 are:

4a^3\cdot (3a),\quad 5a^2\cdot(-7a^2)

their values are respectively

12a^4,\quad -35a^4

and their sum is -23a^4

vekshin12 years ago
5 0

Answer:

- 23

Step-by-step explanation:

We could do this the long way and expand the whole product or note that the a^{4} terms arise from the product of the a³ and a terms and the product of the a² and a² terms, that is

4a³ × 3a = 12a^{4}

+ 5a² × - 7a² = - 35a^{4}

Summing gives

12a^{4} - 35a^{4} = - 23a^{4}

with coefficient - 23

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Answer:

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Step-by-step explanation:

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And remember the little $4308 pizza-mistake? How many weeks would you have
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Solve the equation, keeping the value for x as an improper fraction. 23x = − 12x + 5 1.Isolate the variable by adding 12x to bot
kogti [31]

Answer:

x=\frac{30}{7}

Step-by-step explanation:

We have been given an equation \frac{2}{3}x=-\frac{1}{2}x+5. We are asked to solve our given equation.

First of all, we will add \frac{1}{2}x on both sides of equation to separate x variable on one side of equation.

\frac{2}{3}x+\frac{1}{2}x=-\frac{1}{2}x+\frac{1}{2}x+5

\frac{2}{3}x+\frac{1}{2}x=5

Now, we will make a common denominator.

\frac{2*2}{3*2}x+\frac{1*3}{2*3}x=5

\frac{4}{6}x+\frac{3}{6}x=5

Add numerators:

\frac{4+3}{6}x=5

\frac{7}{6}x=5

Upon multiply both sides of our equation by \frac{6}{7}, we will get:

\frac{6}{7}*\frac{7}{6}x=5*\frac{6}{7}

x=\frac{5*6}{7}

x=\frac{30}{7}

Therefore, the solution for our given equation is x=\frac{30}{7}.

5 0
1 year ago
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The ticker shows trades of stock in Hewlett-Packard (HPQ) ExxonMobil (XOM) and Chevron CTX).
frutty [35]

Question Completion:

Joon bought the shares at this price, and her broker charged her 1% commission. What was the total cost of her investment?

Regne sold the shares of ExxonMobil shown in the above trade and his broker charged him 1.5% commission How much money did the broker receive?

Lisa sold the shares of Chevron indicated above through her discount broker, who charges $28 per transaction.  How much did Lisa receive from the above after the broker took his fee.

Answer:

Trades of Stock in Hewlett-Packard (HPQ) ExxonMobil (XOM) and Chevron CTX)

a. Shares of Hewlett-Packard sold = 6,000 (6K)

b. The total value of all the HP shares sold is $63,780.

c. Total cost of Joan's investment is $64,417.80.

d. Regne's broker received a commission of $3,677.40.

e. Lisa received $760,022.

Step-by-step explanation:

a) Data and Calculations:

Hewlett-Packard (HPQ)    ExxonMobil (XOM)          Chevron CTX)

HPQ 6K10.63 ∨0.23          XOM 3K81.72 ∧ 0.08    CVX 9K84.45 ∨0.22

b) The total value of all the HP shares sold is 6,000 * $10.63

= $63,780

c) Joan's investment:

Investment = $63,780

Broker's commission = 1% = $637.80

Total cost of Joan's investment = $64,417.80 ($63,780 + $637.80)

d) Regne Broker's Commission:

Investment = $245,160 (3,000 * $81.72)

Commission = $3,677.40 ($245,160 * 1.5%)

e) Lisa received from Chevron's stock sale:

Investment = 9,000 * $84.45 = $760,050

Broker's fee = $28

Lisa's receipt = $760,022 ($760,050 - $28)

8 0
1 year ago
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