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alekssr [168]
2 years ago
9

Complete the steps to solve the inequality: 0.2(x + 20) – 3 > –7 – 6.2x Use the distributive property: Combine like terms: Us

e the addition property of inequality: Use the subtraction property of inequality: Use the division property of inequality: 0.2x + 4 – 3 > –7 – 6.2x 0.2x + 1 > –7 – 6.2x 6.4x + 1 >
Mathematics
2 answers:
Rzqust [24]2 years ago
7 0

0.2x+4-3>-7-6.2x

0.2x+1>-7-6.2x

0.2x+0.6x>-8

0.8x>-8

the correct answer is: x>-1.25

IRISSAK [1]2 years ago
3 0
0.2(x + 20) - 3 > -7 - 6.2x.....distribute trhr the parenthesis
0.2x + 4 - 3 > -7 - 6.2x...simplify
0.2x + 1 > - 7 - 6.2x...addition property...add 6.2x to both sides
0.2x + 6.2x + 1 > -7 ...simplify
6.4x + 1 > - 7.....subtraction property....subtract 1 from both sides
6.4x > -7 - 1....simplify
6.4x > -8....division property....divide both sides by 6.4
x > -8 / 6.4...simplify
x > - 1.25 <==
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Answer:

a

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b

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c

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.          

Step-by-step explanation:

From the question we are told we are told that  

   The  equation for the temperature of a cup of coffee place on a counter is

         H= f(t)

Here  t is the time in minutes the  coffee was put on the counter

Generally  f(t)'  is the derivative of  f(t) at it represents the change of the temperature of the cup of coffee with respect to time

 Generally for the coffee placed on the counter after a couple of minutes the temperature will decrease hence  f(t)' is  negative

Generally the unit of the temperature is in degrees Celsius while that of time is  in minutes

  So the change in temperature with time f(35)' will be in degrees Celsius/minutes (i.e  degC/min)

  From the question we are told that

        |f(35)'| =  1.5

i.e  the rate of change of temperature after 35 minutes is  1.5

and

         |f(35)| =  68

i.e the temperature of the cup of coffee after 35 minutes is  67 degC

Now after another   t=  30  seconds =  \frac{30}{60}= 0.5 \ minutes the  rate  of change of the temperature of the cup of  coffee is  

          R =  |f(35)'| *  t

=>        R = 1.5  *  0.5

=>        R = 0.75    

So

At <u>35</u> minutes after the coffee was put on the counter, its temperature is <u>68</u> and will <u>decrease</u> by about <u>0.75</u> in the next 30 seconds.  

     

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