The zeros are 3 and -5. Hope this helps!
Answer:
NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in that both contain plenty of dust and gas. Both also have active star-forming sites.
Step-by-step explanation: Got it right on the test
Answer:
13, 16, 18
Step-by-step explanation:
Sabemos que podemos calcular el total de plumas amarillos, por medio de la media.
16 = (12 + 14 + 15 + 24 + x + y + z) / 7
16 * 7 = 12 + 14 + 15 + 24 + x + y + z
112 = 65 + x + y + z
x + y + z = 112-65
x + y + z = 47
sabemos que la mediana es el valor medio, y que ese 46 debe dividirse entre 3 valores porque son 3 cajas, entonces debemos buscar los números adecuados para el valor 15 esté en la mitad, es decir de cuarto.
Sin meter los valores nuevos, el ranking sería así:
12
14
15
24
el 15 esta de tercero, para que quede de cuarto, debe tener dos valores por debajo y un por arriba, así:
X
12
14
15
y
z
24
Por lo tanto, valores mayores a 15 serían por ejemplo y = 16 y z = 18:
16 + 18 = 34
x = 47-34 = 13
quedaría:
12
13
14
15
dieciséis
18 años
24
Si recalculamos la media:
m = (12 + 14 + 15 + 24 + 13 + 16 + 18) / 7 = 16
Answer:
Initial Fee is $2.
Step-by-step explanation:
Given:
Stops Price (dollars)
3 6.50
7 12.50
11 18.50
Also Given:
The price of a train ticket consists of an initial fee plus a constant fee per stop.
So let the Cost of initial fee be 'x'.
Also Let the Cost of Constant fee be 'y'.
Now Equation can framed as;
Now According to table;
Number of stops = 3
Price = 6.50
So equation can be framed as;
Also According to table;
Number of stops = 7
Price = 12.50
So equation can be framed as;
Now Subtracting equation 1 from equation 2 we get;
Substituting the value of y in equation 1 we get;
Hence Initial Fee is $2.
For this case we have:
Polynomial 1: 
Polynomial 2: 
Sorting the polynomials:
Polynomial 1: 
Polynomial 2:
Adding term to term (similar) we have:
Answer:
