All categories

1 year ago

A wagon can hold 44 pounds. A newspaper weighs 22 ounces. How many newspapers can the wagon hold?

Mathematics

2 answers:

miss Akunina [59]1 year ago

6 0

Answer:

The wagon can hold 32 newspapers

Step-by-step explanation:

Digiron [165]1 year ago

5 0

The wagon can hold 32 newspapers. There are 16 ounces in a pound so multiply 44*16 and then divide it by 22

You might be interested in

Which function has a range of y < 3?

Setler79 [48]

Using a graphing tool

Let's graph each of the cases to determine the solution of the problem

case A) $y=3(2^{x})$

see the attached figure N $1$

The range is the interval--------> (0,∞)

$y> 0$

therefore

the function $y=3(2^{x})$ is not the solution

case B) $y=2(3^{x})$

see the attached figure N $2$

The range is the interval--------> (0,∞)

$y> 0$

therefore

the function $y=2(3^{x})$ is not the solution

case C) $y=-2^{x}+3$

see the attached figure N $3$

The range is the interval--------> (-∞,3)

$y< 3$

therefore

the function $y=-2^{x}+3$ is the solution

case D) $y=2^{x}-3$

see the attached figure N $4$

The range is the interval--------> (-3,∞)

$y>-3$

therefore

the function $y=2^{x}-3$ is not the solution

the answer is

$y=-2^{x}+3$

5 0

2 years ago

Read 2 more answers

If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?

kiruha [24]

Answer:

$[1,\infty)$

Step-by-step explanation:

$b(x)=\sqrt{x-4}$

$a(x)=3x+1$

Since we want to know the domain of $(b \circ a)(x)$ , let's first consider the domain of the inside function, that is, that of $a(x)=3x+1$ . Every polynomial function has domain all real numbers.

So we can plug anything for function $a$ and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find $(b \circ a)(x)$ and simplify now.

$(b \circ a)(x)$

$b(a(x))$

$b(3x+1)$

$\sqrt{(3x+1)-4}$

$\sqrt{3x+1-4}$

$\sqrt{3x-3}$

Now again we can only square root positive or zero numbers so we want $3x-3 \ge 0$ .

Let's solve this to find the domain of $(b \circ a)(x)$ .

$3x-3 \ge 0$

Add 3 on both sides:

$3x \ge 3$

Divide both sides by 3:

$x \ge 1$

So we want $x$ to be a number greater than or equal to 1.

The option that says this is $[1,\infty)$

-------------------------------

Give an example why option A fails:

A number in the given set is -2.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(-2)=3(-2)+1=-6+1=-5$ and $b(-5)=\sqrt{-5-4}=\sqrt{-9} \text{ which is not real}$ .

Give an example why option B fails:

A number in the given set is 0.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(0)=3(0)+1=0+1=1$ and $b(1)=\sqrt{1-4}=\sqrt{-3} \text{ which is not real}$ .

Give an example why option D fails:

While all the numbers in set D work, there are more numbers outside that range of numbers that also work.

A number not in the given set that works is 3.

$a(x)=3x+1$

$b(x)=\sqrt{x-4}$

So $a(3)=3(3)+1=9+1=10$ and $b(1)=\sqrt{10-4}=\sqrt{6} \text{ which is real}$ .

4 0

2 years ago

Read 2 more answers

There are some nickels dimes and quarters in a large piggy bank for every two nickels there are 3 dimes for every two dimes that

creativ13 [48]

We are given

piggy bank has nickels , dimes and quarters

Let's assume

number of nickels =n

every two nickels there are 3 dimes

so, number of dimes are

$=\frac{3}{2}n$

$=1.5n$

every two dimes that are 5 quarters there

so, number of quarters are

$=\frac{5}{2}\times 1.5n$

$=3.75n$

so, total number of coins = number of nickels + number of dimes +number of quarters

total number of coins =n+1.5n+3.75

there are 500 coins

so, we get

$n+1.5n+3.75n=500$

now, we can solve for n

$6.25n=500$

divide both sides by 6.25

so, we get

$n=80$

number of dimes is 1.5n

$=1.5\times 80$

$=120$

number of quarters is 3.75n

$=3.75\times 80$

$=300$

so,

Number of nickels =80

Number of dimes =120

Number of quarters =300............Answer

6 0

2 years ago

Jessica rides the bus 8and 4/5 miles each day. WHATS is The total Numbers of miles she rindes in 21 day's

lesantik [10]

201 miles i believe, hope this helps!

5 0

2 years ago

Read 2 more answers

A garden supply store sells two types of lawn mowers. The smaller mower costs $249.99 and the larger mower costs $329.99. If 30

Annette [7]

19 small mowers and 11 large mowers are sold

Solution:

Let "a" be the number of small mowers sold

Let "b" be the number of large mowers sold

Cost of each small mower = $ 249.99

Cost of each large mower = $ 329.99

30 total mowers were sold

Therefore,

a + b = 30

a = 30 - b ------------- eqn 1

The total sales for a given year was $8379.70

Thus we frame a equation as:

number of small mowers sold x Cost of each small mower + number of large mowers sold x Cost of each large mower = 8379.70

$a \times 249.99 + b \times 329.99 = 8379.70$

249.99a + 329.99b = 8379.70 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

249.99(30 - b) + 329.99b = 8379.70

7499.7 - 249.99b + 329.99b = 8379.70

80b = 8379.70 - 7499.7

80b = 880

Divide both sides by 80

b = 11

Substitute b = 11 in eqn 1

a = 30 - 11

a = 19

Thus 19 small mowers and 11 large mowers are sold

8 0

2 years ago