Given:
A quadratic function has a line of symmetry at x = –3.5 and a zero at –9.
To find:
The other zero.
Solution:
We know that, the line of symmetry divides the graph of quadratic function in two congruent parts. So, both zeroes are equidistant from the line of symmetry.
It means, line of symmetry passes through the mid point of both zeroes.
Let the other zero be x.

Multiply both sides by 2.

Add 9 on both sides.


Therefore, the other zero of the quadratic function is 2.
a, b, c - side lengths (a ≤ b ≤ c)
If
, then is Obtuse triangle.
If
, then is Right triangle.
If
, then Acute triangle.

Check to see if the sum of the first two sides is greater than the third.

, therefore is Scalene triangle.

It's Obtuse triangle.
A) 180 would be expected to pass.
B) The standard deviation is 4.
C) 95% of people would fall between 172 and 188.
D) Yes, this is more than 3 standard deviations below the mean.
Explanation
A) Multiply the probability by the sample size:
0.6(300) = 180
B) Standard deviation is found by:
√n(p)(1-p)
For our data, we have:
√300(0.6)(0.4) = 4
C) Two standard deviations below the mean is 180-2(4) = 172; two standard deviations above the mean is 180+2(4)= 188.
D) Three standard deviations below the mean is 180-3(4) = 168; 134 is more than this below the mean. 99.7% of data fall within 3 standard deviations of the mean; 0.15% fall below this point, so yes, this is unusually low.
7.2(2.8r-4.5s)+9.34r -1.25s
=20.16r - 32.4 +9.34r -1.25s
=29.5r - 33.65s
So the answer is A
hope I can help u
Answer:
Step-by-step explanation:
h(t) = 0.3t -t +21t , t=time and h=height
1.
at t=0 the hight is h=0
h(0) = 0.3*0 -0 +21*0 = 0
It makes sense that at the time 0 seconds when the rollercoaster did not leave the hight is 0 feet.
2.
for t=10 substitute t with 10
h(10) = 0.3*10 -10 +21*10 = 3 -10 +210 = 203
3. see graph
4. the rollercoaster is going up