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irina1246 [14]
2 years ago
6

In a large​ city, 6060​% of people pass the​ drivers' road test. suppose that every​ day, 300300 people independently take the t

est. complete parts​ (a) through​ (d) below.
a. what is the number of people who are expected to​ pass? the expected number is 180180. ​(round to the nearest whole number as​ needed.)
b. what is the standard deviation for the number expected to​ pass? the standard deviation is nothing. ​(round to the nearest whole number as​ needed.)
c. after a great many​ days, according to the empirical​ rule, on about​ 95% of these​ days, the number of people passing will be as low as​ _____ and as high as​ _____. (hint: find two standard deviations below and two standard deviations above the​ mean.) after a great many​ days, according to the empirical​ rule, on about​ 95% of these​ days, the number of people passing will be as low as nothing and as high as nothing. ​(round to the nearest whole number as​ needed.)
d. if you found that one​ day, 134134 out of 300300 passed the​ test, would you consider this to be a very lowlow ​number? ▼ yes, no, because 134134 is ▼ less than 1 standard deviation between 1 and 2 standard deviations between 2 and 3 standard deviations more than 3 standard deviations belowbelow the mean.
Mathematics
1 answer:
erma4kov [3.2K]2 years ago
8 0
A) 180 would be expected to pass.
B) The standard deviation is 4.
C) 95% of people would fall between 172 and 188.
D) Yes, this is more than 3 standard deviations below the mean.

Explanation
A) Multiply the probability by the sample size:
0.6(300) = 180

B) Standard deviation is found by:
√n(p)(1-p)
For our data, we have:
√300(0.6)(0.4) = 4

C) Two standard deviations below the mean is 180-2(4) = 172; two standard deviations above the mean is 180+2(4)= 188.

D) Three standard deviations below the mean is 180-3(4) = 168; 134 is more than this below the mean.  99.7% of data fall within 3 standard deviations of the mean; 0.15% fall below this point, so yes, this is unusually low.
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Lines AB and CD and are parallel. Find the measures of the three angles in triangle ABF.
Airida [17]

Answer:    ∠B = 42°   ∠A = 23°  ∠F = 115°

Step-by-step explanation:

∠B≅∠C  alternate interior angles  42°

  ∠CDF is supplementary to ∠CDE,

so m∠CDF = 23°  and ∠FAB≅∠CDF so m∠FAB= 23°

<em>also ∠A ≅ CDE  corresponding angles  157° ∠FAB is suplementary to ∠A </em>

<em>so 180 - 157 = 23 gives the m∠FAB</em>

The sum of the angles of a triangle is 180°, so m∠AFB = 180 -(23 +42)

180- 65 = 115 = m∠F

3 0
2 years ago
Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h. She writes the expre
gtnhenbr [62]

Answer: The meaning of each term of the  Madison’s and Tyler’s expressions is mentioned below.

Step-by-step explanation:

Since, when Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h.

That is, after 1 hour total number of amoebas = 3×1000 = 3^1\times 1000

After 2 hour,  total number of amoebas = 3×3000=3^2\times 100

After 3 hour, total number of amoebas = 3×9000= 3^3\times 1000

similarly, after h hours, total number of amoebas,

f(h) = 3^h\times 1000

where, 1000 is the initial population of amoeba 3 is the growth factor of population and f(h) is the population of amoeba after h hours.

Since, when Tyler starts with a population of 1 amoeba that  increases 30% in size every hour for a number of hours.

That is, after 1 hour total number of amoebas = (1+0.3)^1

After 2 hour,  total number of amoebas =  (1+0.3)^2

After 3 hour, total number of amoebas =  (1+0.3)^3

Similarly, after h hours, total number of amoebas,

f(h) =(1+0.3)^h

Where,  1 is the initial population of amoeba, 0.3 is the growth rate and 1.3 is the growth factor.


5 0
2 years ago
Read 2 more answers
For tall heterozygotes with antennae, the offspring are: tall-antennae 46 dwarf-antennae 7 dwarf-no antennae 42 tall-no antennae
Dmitriy789 [7]

Answer: 46%

Step-by-step explanation:

Recombination frequency =Number of recombinant offspring ÷ total number of offspring × 100%

Number of recombinant offspring= 46 ( number of offspring with the same genetic combination as the parent which in this case are the tall antennae TA)

Total number of offspring = 46+7+5+42= 100

Recombination frequency= 46/100 × 100%

=46%

Thanks

8 0
2 years ago
Charlie gathers apples, pears, and plums. The numbers of apples and plums are 10-partners. There are the same number of apples a
aalyn [17]

Answer:

<u>The total number of pieces of fruit that Charlie can gather ranges from 11 to 19.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Numbers of apples and plums are 10-partners, it means that the sum of apples and plums is 10.

Number of apples and pears are the same.

2. How many pieces of fruit can Charlie gather?

Apples = a

Plums = p

Pears = s

a + p = 10

Possible values of a and p:

1 + 9, 2 + 8, 3 + 7, 4 + 6, 5 + 5, 6 + 4, 7 + 3, 8 + 2, 9 + 1

Possible values of s:

1, 2, 3, 4, 5, 6, 7, 8, or 9

<u>Therefore, the total number of pieces of fruit that Charlie can gather ranges from 11 to 19.</u>

7 0
2 years ago
The lengths, in order, of four consecutive sides of an equiangular hexagon are 1, 7, 2 and 4 units, respectively. What is the su
DedPeter [7]

Answer:

9

Step-by-step explanation:

Extend every other side of the hexagon so that a triangle is formed.  Since the hexagon is equiangular, the overall triangle is an equilateral triangle, as well as the smaller triangles in the corners.

The length of the sides of the overall triangle is 7 + 2 + 4 = 13.

Therefore, the other two sides of the hexagon are 5 and 4.

The sum is 5 + 4 = 9.

8 0
2 years ago
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