Ask question

Ask question

All categories

2 years ago

14

An inspector checks 98 cell phones and finds that 2 of them are defective. A company has 850 of these phones. How many of the co

mpany's phones are likely to be defective?

1 answer:

jekas [21]2 years ago

3 0

Answer:

17

Step-by-step explanation:

As 2 phones are defective from a group of 98 that were checked, you can determine a percentage:

2/98= 2%

This indicates that 2% of the phones are likely to be defective and because of that you can find 2% of 850:

850*2%= 17

According to this, 17 phones are likely to be defective.

You might be interested in

Solve the equation 5x + (−2) = 6x + 4 using the algebra tiles. What tiles need to be added to both sides to remove the smaller x

miss Akunina [59]

Answer:

a) Adding -5x on both sides of the equation to remove the smaller x-coefficient

b) Adding -4 on both sides will remove the constant from the right side of the equation

Step-by-step explanation:

Given equation:

5x + (−2) = 6x + 4

a) What tiles need to be added to both sides to remove the smaller x-coefficient?

Smaller x-coefficient is 5x to remove the smaller x-coefficient

So, Adding -5x on both sides of the equation to remove the smaller x-coefficient

b) What tiles need to be added to both sides to remove the constant from the right side of the equation?

the constant on right side is 4

Adding -4 on both sides will remove the constant from the right side of the equation

6 0

2 years ago

Read 2 more answers

the weight of a bag of golf balls varies directly as the number of golf balls in the bag.If a bag of 69 gold balls weighs 2,553

seropon [69]

Answer: 30

Step-by-step explanation:

Given :The weight of a bag of golf balls varies directly as the number of golf balls in the bag.

Let x be the number of golf balls in a bag that weighs 1,110 grams.

Then we have the following direct variation equation,

$\dfrac{x}{1110}=\dfrac{69}{2553}$

Multiply 1110 both sides , we get

$x=\dfrac{69}{2553}\times1110=30$

Hence, there are 30 balls in the bag.

4 0

2 years ago

Which score has a higher relative position, a score of 271.2 on a test for which = 240 and , or a score of 63.6 on a test for wh

Fittoniya [83]

Answer:

The score of 271.2 on a test for which xbar = 240 and s = 24 has a higher relative position than a score of 63.6 on a test for which xbar = 60 and s = 6.

Step-by-step explanation:

Standardized score, z = (x - xbar)/s

xbar = mean, s = standard deviation.

For the first test, x = 271.2, xbar = 240, s = 24

z = (271.2 - 240)/24 = 1.3

For the second test, x = 63.6, xbar = 60, s = 6

z = (63.6 - 60)/6 = 0.6

The standardized score for the first test is more than double of the second test, hence, the score from the first test has the higher relative position.

Hope this Helps!!!

3 0

1 year ago

Suppose that only 20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions whe

Lina20 [59]

Answer:

a) 91.33% probability that at most 6 will come to a complete stop

b) 10.91% probability that exactly 6 will come to a complete stop.

c) 19.58% probability that at least 6 will come to a complete stop

d) 4 of the next 20 drivers do you expect to come to a complete stop

Step-by-step explanation:

For each driver, there are only two possible outcomes. Either they will come to a complete stop, or they will not. The probability of a driver coming to a complete stop is independent of other drivers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

20% of all drivers come to a complete stop at an intersection having flashing red lights in all directions when no other cars are visible.

This means that $p = 0.2$

20 drivers

This means that $n = 20$

a. at most 6 will come to a complete stop?

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{20,0}.(0.2)^{0}.(0.8)^{20} = 0.0115$

$P(X = 1) = C_{20,1}.(0.2)^{1}.(0.8)^{19} = 0.0576$

$P(X = 2) = C_{20,2}.(0.2)^{2}.(0.8)^{18} = 0.1369$

$P(X = 3) = C_{20,3}.(0.2)^{3}.(0.8)^{17} = 0.2054$

$P(X = 4) = C_{20,4}.(0.2)^{4}.(0.8)^{16} = 0.2182$

$P(X = 5) = C_{20,5}.(0.2)^{5}.(0.8)^{15} = 0.1746$

$P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091$

$P(X \leq 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 + 0.1091 = 0.9133$

91.33% probability that at most 6 will come to a complete stop

b. Exactly 6 will come to a complete stop?

$P(X = 6) = C_{20,6}.(0.2)^{6}.(0.8)^{14} = 0.1091$

10.91% probability that exactly 6 will come to a complete stop.

c. At least 6 will come to a complete stop?

Either less than 6 will come to a complete stop, or at least 6 will. The sum of the probabilities of these events is decimal 1. So

$P(X < 6) + P(X \geq 6) = 1$

We want $P(X \geq 6)$ . So

$P(X \geq 6) = 1 - P(X < 6)$

In which

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0115 + 0.0576 + 0.1369 + 0.2054 + 0.2182 + 0.1746 = 0.8042$

$P(X \geq 6) = 1 - P(X < 6) = 1 - 0.8042 = 0.1958$

19.58% probability that at least 6 will come to a complete stop

d. How many of the next 20 drivers do you expect to come to a complete stop?

The expected value of the binomial distribution is

$E(X) = np = 20*0.2 = 4$

4 of the next 20 drivers do you expect to come to a complete stop

4 0

2 years ago

A rectangular room has a width of 5 yards and length of 6 yards. How many square-feet carpet will be required for carpeting the

Sindrei [870]

Answer:

Option B $270\ ft^{2}$

Step-by-step explanation:

we know that

The area of the rectangle room, is equal to

$A=LW$

where

L is the length

W is the width

we have

$L=6\ yd$

$W=5\ yd$

Remember that

1 yard= 3 feet

Convert yards to feet

$L=6*3=18\ ft$

$W=5*3=15\ ft$

The area is equal to

$A=(18)(15)=270\ ft^{2}$

4 0

1 year ago