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larisa [96]
2 years ago
11

You have at most $3.65 to make copies for a school project. Each copy costs $0.25. Write and solve an inequality that represents

the number of copies you can make.
Mathematics
1 answer:
slamgirl [31]2 years ago
5 0

The equation for the problem is 0.25x ≤ 3.65

Hope it helps!

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"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt
Westkost [7]

Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b) Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c) P(\bar X >31.25)=0.006=0.6\%

d) P(\bar X >28.25)=0.9997=99.97\%

e) P(28.25

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =30,\sigma =2)

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

b. What is the standard error of the mean time?

The standard error is given by this formula:

Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >31.25)=1-P(\bar X

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}

And we want to find this probability:

P(\bar X >28.25)=1-P(\bar X

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

P(28.25

3 0
2 years ago
The triangle below has been reduced by a scale of 0.4. A large triangle has a base of 30 centimeters and height of 10 centimeter
egoroff_w [7]

Answer:

24 centimeters squared(cm²)

Step-by-step explanation:

The triangle below has been reduced by a scale of 0.4.

A large triangle has a base of 30 centimeters and height of 10 centimeters.

Hence, reducing the large triangle by the given scale ratio, we have :

Height = 10cm × 0.4 = 4cm

Base = 30cm × 0.4 = 12 cm

Hence, the area of the smaller triangle

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Base = 12 cm

Area = 1/2 × 4 × 12

= 24 cm²

7 0
2 years ago
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A snack food manufacturer buys corn for tortilla chips from two cooperatives, one in Iowa and one in Illinois. The price per uni
aleksandrvk [35]

Answer:

a. <u>x1 = No. of units to purchase from Iowa</u>

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<u></u>

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<u></u>

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Step-by-step explanation:

a. We can consider the variables x1 and x2 as:

<u>x1 = No. of units to purchase from Iowa</u>

<u>x2 = No. of units to purchase from Illinois</u>

<u></u>

b. Price per unit of Iowa corn = $6

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Objective function that would minimize the total cost can be written as:

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The constraints for these conditions are:

<u>x1 + x2 ≥ 12000</u>

<u>x1 ≤ 8000</u>

<u>x2 ≥ 6000</u>

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2 years ago
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Answer:

C- Box in the top right corner!

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2 years ago
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In the table, x represents the age in years of a collectible baseball card, and y represents its value in dollars. Cost of a Pac
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