Option B:
Option C: The length of line segment PR is 13 units.
Explanation:
Given that the circle is inscribed in triangle PRT. Points Q, S, and U of the circle are on the sides of the triangle. Point Q is on side P R, point S is on side R T, and point U is on side P T.
The length of RS is 5, the length of PU is 8 and the length of UT is 6.
Option A: The perimeter of the triangle is 19 units.
The perimeter of the triangle is given by
Perimeter of ΔPRT = PU + UT + TS + SR + RQ + QP
Since, P, T and R are tangents to the circle and we know that "Tangents to a circle drawn to a point outside the circle are equal in length".
Thus, we have,
RS = RQ = 5
PU = PQ = 8 and
UT = TS = 6
Substituting the values in the perimeter of ΔPRT, we get,
Perimeter of ΔPRT = 8 + 6 + 6 + 5 + 5 + 8 =38 units
Thus, the perimeter of the triangle is 38 units.
Hence, Option A is not the correct answer.
Option B :
Since, P, T and R are tangents to the circle and we know that "Tangents to a circle drawn to a point outside the circle are equal in length".
Then
Hence, Option B is the correct answer.
Option C: The length of line segment PR is 13 units.
The length of PR is given by
PR = PQ + QR
Substituting the values RQ = 5 and PQ = 8, we get,
PR = 5 + 8 = 13 units
Thus, the length of line segment PR is 13 units.
Hence, Option C is the correct answer.
Option D: The length of line segment TR is 10 units.
The length of TR is given by
TR = TS + SR
Substituting the values TS = 6 and SR = 5, we get,
TR = 6 + 5 = 11 units
Thus, the length of line segment TR is 11 units
Hence, Option D is not the correct answer.
For this case, the parent function is given by:
We apply the following transformations:
Vertical translations:
Suppose that k> 0
To graph y = f (x) + k, move the graph of k units upwards:
For k = 9 we have:
Horizontal translations:
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right
For h = 4 we have:
Answer:
The function g (x) is given by: