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marin [14]
1 year ago
6

What is the value of x? Enter your answer, as a decimal, in the box. x= A right triangle with vertices labeled as A, B, and C. S

ide C B is the base and the top vertex is A. Side A B contains a midpoint D. A line segment drawn from C to D bisects angle A C B into two parts labeled as A C D and B C D. Angles A C D and B C D are marked with single arc. Side A C is labeled as 5. Base C B is labeled as 6. Segment A D is labeled as x. Segment B D is labeled as 4.2.
Mathematics
1 answer:
____ [38]1 year ago
6 0

x=3.95

Explanation

From the given information we find that the triangle is right angled at C. CB is the base,AC is the height and AB is the hypotenuse.

Given that D is the hypotenuse of the hypotenuse AB.

BC=6

BD=4.2

AD=x

the height and the base of the triangle is given.

Using pythagoras theorem, we can find the hypotenuse AB.

AB=\sqrt{AC^2+CB^2} \\=\sqrt{5^2+6^2} \\=\sqrt{25+36} \\=\sqrt{61} \\

D is the midpoint of AB

therefore AD=AB/2=\sqrt{61}/2

=3.905

x=3.905 cm

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There is a safety fence around a circular pool with a gate. The gate is 150 cm wide. What is the length of the fence not includi
Zolol [24]

Answer:

The length of the fence is 6.28x-150 cm.

Step-by-step explanation:

Let the circular pool has the radius (r ) = x cm.

Since the pool is in a circular shape so the circumference will be the length of the fence. Moreover, there is a 150cm wide so we have to subtract the 150 cm from the value of circumference in order to get the actual length of the fence.

Length of fence  = Circumference of the pool – width of the gate.

Length of fence = 2 π r – 150

Length of fence = 2 × 3.14 × x – 150

Length of fence = 6.28x – 150 cm.

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1 year ago
3 (n - 1) + 2 (n + 2)
Vikentia [17]
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(3n + 2n) + (-3 + 4)
5n + 1
5 0
2 years ago
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Dean is comparing prices on ground beef. Store A is selling 5 pounds of ground beef for $23.49. Store B is selling 8 pounds of g
pentagon [3]

Answer: Store B

Step-by-step explanation:

3 0
1 year ago
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The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
2 years ago
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In whatever way we find reference angles,

cos will remain cos only and sin will remain sin only there may be only changes in sign.

Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos.  Hence these options cannot be for reference angles.

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ie reference angle of orignal angle t = 180+t

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