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vovikov84 [41]
2 years ago
10

Divide $3,300 into three parts whose ratio is 1:3:7.

Mathematics
1 answer:
AveGali [126]2 years ago
8 0
1+3+7=11

The first part is
3,300×(1÷11)
=300
The second part is
3,300×(3÷11)
=900
the third part is
3,300×(7÷11)
=2,100
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Troy has a price chart below for various ingredients he needs to order for his sandwich bar. Sandwich Ingredients Item Cost (per
shepuryov [24]

Answer:

$93.75

Step-by-step explanation:

The computation of the total cost of order is shown below:

The Cost of 8 pounds of Pepperoni is

=  8 × $3.15

= 25.2

The Cost of 15 pounds of cheese is

= 15 × $1.85

= $27.75

The Cost of 12 pounds of sausage is

= 12 × $3.40

= $40.8

So, The total cost is

= $25.2 + 27.75 + $40.80

= $93.75

4 0
1 year ago
What effect will a translation 3 units down and 2 units left have on the polygon? Be sure to address how it could impact the ang
Tanzania [10]
For the answer to the question above, when you carry your jewelry box or your phone 3 floors down 
and 2 miles to the left, the angles and side lengths don't change, 
and it still looks exactly the same as it did before you picked it up 
and moved it.

Translation can't change angles or lengths.  And if those don't 
change, then the later shape is congruent to the earlier shape.
8 0
1 year ago
Read 2 more answers
A liquid dietary product implies in its advertising that use of the product for one month results in an average weight loss of a
BigorU [14]

Answer:

Following are the responses to the given question:

Step-by-step explanation:

Please find the table in the attached file.

mean and standard deviation difference: \bar{d}=\frac{\Sigma d}{n} =\frac{-4-6-.......-4-4}{8}=-4.125 \\\\S_d=\sqrt{\frac{\Sigma (d-\bar{d})^2 }{n-1}}=\sqrt{\frac{(-4 + 4.125)^2 +.......+(-4 +4.125)^2 }{8-1}}= 1.246

For point a:

hypotheses are:

H_0 : \mu_d \geq -3\\\\H_a : \mu_d < -3\\\\

degree of freedom:

df=n-1=8-1=7

 From t table, at\alpha = 0.05, reject null hypothesis if t.

test statistic:  

t=\frac{\bar{d}-\mu_d }{\frac{s_d}{\sqrt{d}}}=\frac{ -4.125- (-3)}{\frac{1.246}{ \sqrt{8}}} =-2.55

because the t=-2.553, removing the null assumption. Data promotes a food product manufacturer's assertion with a likelihood of Type 1 error of 0.05.

For point b:

From t table, at \alpha =0.01, removing the null hypothesis if t.

because t=-2.553 >-2.908, fail to removing the null hypothesis.  

The data do not help the foodstuff producer's point with the likelihood of a .01-type mistake.

For point c:

Hypotheses are:

H_0: \mu_d \geq -5\\\\H_a: \mu_d < -5

Degree of freedom:

df=n-1=8-1=7

From t table, at \alpha =0.05, removing the null hypothesis if t.

test statistic:  t=\frac{\bar{d}-\mu_d}{\frac{s_d}{\sqrt{n}}} =\frac{-4.125-(-5)}{\frac{1.246}{\sqrt{8}}}=1.986

Since t-1.986 >-1.895, The null hypothesis fails to reject. The results do not support the packaged food producer's claim with a Type 1 error probability of 0,05.

From t table, at\alpha= 0.01, reject null hypothesis ift.

Since t=1.986>-2.998 , fail to reject null hypothesis.  

Data do not support the claim of the producer of the dietary product with the probability of Type 1 error of .01.

5 0
1 year ago
ALGEBRA 2/ TRIG QUESTION ATTACHED Please help ❤️❤️
ss7ja [257]
Let's calculate the value of angle A and B

sin(A) =-4/5 → sin⁻¹(- 4/5) = A  →  A = - 53.13


cos(B) = -5/13 → cos⁻¹ (- 5/13) = B  → B = 112.62


tan (A+B) = sin(A+B)/cos(A+B)  with A+B = -53.13 + 112.62 = 59.49

tan (A+B) = sin(59.49)/cos(59.49) = 0.86154/0.507688 = 1.6969.

(Answer H = 56/33 = 1.6969)

7 0
1 year ago
A company currently has 200 units of a product on hand that it orders every 2 weeks when the salesperson visits the premises. De
disa [49]

Answer: 289 units

Step-by-step explanation:

Given the following :

Inventory (I) = 180

Lead time (L) = 7 days

Review time (T) = 2 weeks = 14 days

Demand (D) = 20

Standard deviation (σ) = 5

Zscore for 95% probability = 1.645

Units to be ordered :

D(T + L) + z(σT+L)

(σT+L) = √(T + L)σ²

= √(14 + 7)5²

= √(21)25

= 22.9

D(T + L) + z(σT+L) - I

20(14 + 7) + 1.645(22.9 + 7) - I

= 420 + 49.1855 - 180

= 289.1855

= 289 quantities

5 0
2 years ago
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