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Nikitich [7]
1 year ago
6

A plane intersects a prism parallel to the base of the prism. The cross section is a polygon with eight sides. The base of the p

rism has how many sides?
Mathematics
2 answers:
Ksenya-84 [330]1 year ago
7 0
I'm not quite sure but I believe the answer to your question is 4 sides
maxonik [38]1 year ago
4 0

Answer:

wouldn't it be 6

Step-by-step explanation:

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Using the side-splitter theorem, which segment length would complete the proportion?
tia_tia [17]

we know that

<u>The Side-Splitter Theorem</u>: States that If a line is parallel to one side of a triangle and intersects the other two sides, then it divides those two sides proportionally

so

in this problem

\frac{GH}{HE} =\frac{GJ}{JF}

therefore

<u>the answer is</u>

The segment length is GJ

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2 years ago
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What is the value of the digit 6 in the number 48.061?
Gwar [14]

Answer:

The hundredths place.

Step-by-step explanation:

48 is the whole number, and .061 is the decimals. As you probably know, this is the whole numbers place value.

ones, tens, hundreds, thousand, 10 thousand, 100 thousand, million...ect.

The decimal places are different

in this case the 0 is the tenths<u> </u>

the 6 is the hundredths

and the 1 is the thousandths.

Mostly, the decimal points are just with added ths to the end.

Hope this helped :D

8 0
1 year ago
The density of air is approximately 1.225 kg/m^3 what is the volume of a soccer ball if the mass of the air it contains is 0.08
svetoff [14.1K]
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8 0
1 year ago
Investigate the following harvesting model both qualitatively and analytically. If a constant number h of fish are harvested fro
zalisa [80]

Answer:

a. The population does not become extinct in finite time.

Step-by-step explanation:

The model for the population of the fishery is

dP/dt = P(a-bP)-h, P(0) = P_0

If we rearrange and replace the constants we have:

\frac{dP}{P(7-P)-49/4} =dt\\\\-4 (\frac{dP}{4(P-7)P+49}) =dt\\\\-4 \frac{dP}{(2P-7)^2} =dt\\\\-4 \int\frac{dP}{(2P-7)^2} =\int dt\\\\-4(-\frac{1}{2(2P-7)})=t+C\\\\\frac{2}{2P-7}=t+C\\\\ t=0 \,\,\, P(0)=P_0\\\\\frac{2}{2P_0-7}=0+C\\\\C=\frac{2}{2P_0-7}

Now we can calculate if the population become 0 in any finite time

\frac{2}{2P-7}=t+\frac{2}{2P_0-7}\\\\\frac{2}{2*0-7}=t+\frac{2}{2P_0-7}\\\\-\frac{2}{7}=t+\frac{2}{2P_0-7}\\\\

To be a finite time, t>0

t=-\frac{2}{7}-\frac{2}{2P_0-7}=0\\\\-\frac{2}{2P_0-7}=\frac{2}{7}\\\\7-2P_0=7\\\\P_0=0

We can conclude that the only finite time in which P=0 is when the initial population is 0.

Because P0 is a positive constant, we can say that the population does not become extint in finite time.

5 0
1 year ago
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