What is √6 divided by √5 in simplest radical form?

Product A is an 8oz. Bottle of cough medicine that sells for $1.36. Product B is a 16oz. Bottle cough medicine that costs $3.20.

Pavlova-9 [17]

Product A= 8oz = 1.36 x 2= 2.72. 16oz = 2.72

product B=16oz= 3.20

so Product A has the lower unit price.

6 0

2 years ago

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Data on average high temperatures (in degrees Fahrenheit) in July and precipitation (in inches) in July for 48 cities is used

wel

Answer:

Explained below.

Step-by-step explanation:

The regression equation to predict amount of precipitation (in inches) in July from the average high temperatures (in degrees Fahrenheit) in July is as follows:

PRECIP = 2.0481 + 0.0067 HIGH

(1)

The value of the slope of the regression line is, 0.0067.

(2)

The predictor variable in this context is the average high temperatures (in degrees Fahrenheit) in July.

(3)

The response variable in this context is the amount of precipitation (in inches) in July.

(4)

The slope of a regression line is average rate of change in the dependent variable with one unit change in the independent variable.

The slope here is 0.0067.

This value implies that the average rate of change in the amount of precipitation (in inches) in July increases by 0.0067 inches with every 1°F increase in the average high temperatures.

(5)

Compute the mount of precipitation for a city that has an average high temperature in July of 87.31°F as follows:

PRECIP = 2.0481 + 0.0067 HIGH

= 2.0481 + 0.0067 × 87.31°F

= 2.633077

≈ 2.63 inches.

5 0

1 year ago

a motor boat traveled 18 miles down a river in 2 hours but took 4.5 hours to return upstream. Find the rate of the motor boat in

tangare [24]

Answer:

rate of the boat in still water = 6.5 miles / hour

rate of the current = 2.5 miles / hour.

Explanation:

1) Name the two variables:

c: rate of the current

b: rate of the boat in still water:

With that, the net rates of the boat down the river and upstrean are:

down the river: b + c

upstream: b - c

2) Now set the equations for the distance as a function of the times and the rates:

distance = rate × time

downstream: 18 miles = (b + c) × 2 hours

upstream: 18 miles = (b - c) × 4.5 hours

3) Set the system of equations:

18 = 2(b + c) ⇒ 9 = b + c . . . Equation (1)

18 = 4.5 (b - c) ⇒ 4 = b - c . . . Equation (2)

4) Solve the system by elimination:

Add equations (1) and (2): 9 + 4 = 2b

Divide both sides by 2: 13/2 = b

Simplify: b = 6.5

Replace b with 6.5 in equation (2) and solve:

4 = 6.5 - c ⇒ c = 6.5 - 4 = 2.5

5) Results:

b = rate of the boat in still water = 6.5 miles / hour

c = rate of the current = 2.5 miles / hour.

3 0

1 year ago

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Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot

Anastasy [175]

Option B : $\frac{1}{\sqrt[3]{x^{5} } }$ is the expression equivalent to $x^{-\frac{5}{3}$

Explanation:

The given expression is $x^{-\frac{5}{3}$

Rewriting the expression $x^{-\frac{5}{3}$ using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

$\frac{1}{x^{\frac{5}{3} } }$

Simplifying, we get,

$\frac{1}{\left(x^{5}\right)^{\frac{1}{3}}}$

Applying the rule, $a^{\frac{1}{n}}=\sqrt[n]{a}$

Thus, we have,

$\frac{1}{\sqrt[3]{x^{5} } }$

Now, we shall determine from the options that which expression is equivalent to $x^{-\frac{5}{3}$

Option A: $\frac{1}{\sqrt[5]{x^{3} } }$

The expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[5]{x^{3} } }$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option A is not the correct answer.

Option B: $\frac{1}{\sqrt[3]{x^{5} } }$

The expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $\frac{1}{\sqrt[3]{x^{5} } }$ is equivalent to $x^{-\frac{5}{3}$

Hence, Option B is the correct answer.

Option C: $-\sqrt[3]{x^5}$

The expression $-\sqrt[3]{x^5}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[3]{x^5}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option C is not the correct answer.

Option D: $-\sqrt[5]{x^3}$

The expression $-\sqrt[5]{x^3}$ is not equivalent to the simplified expression $\frac{1}{\sqrt[3]{x^{5} } }$

Thus, the expression $-\sqrt[5]{x^3}$ is not equivalent to $x^{-\frac{5}{3}$

Hence, Option D is not the correct answer.

4 0

1 year ago

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The junior class is selling Caramel Apple lollipops and Gourmet lollipops to raise money for prom. They profit 50 cents and 75 c

Likurg_2 [28]

If we letx as the number of Caramel Apple lollipops soldy as the number of Gourmet lollipops sold
Then, we can make an inequality from the given which is0.50x + 0.75y ≥ 250The graph of this inequality would have a y intercept of500 and a slope of 2/3 and includes all the points above the solid line.
hope this helps and brainliest :)

6 0

1 year ago

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