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andrew11 [14]
2 years ago
11

Luisa and Connor had $360 altogether . After Connor gave Luisa 2/5 of his money, she had the same amount of money has he did. Ho

w much money did Connor have in the beginning?
Mathematics
1 answer:
Liula [17]2 years ago
8 0

Answer:

$300

Step-by-step explanation:

Let's say that L is the amount of money Luisa had in the beginning, and C is the amount of money Connor had in the beginning.

C + L = 360

C - 2/5 C = L + 2/5 C

Simplifying the second equation:

3/5 C = L + 2/5 C

1/5 C = L

Substituting into the first equation:

C + 1/5 C = 360

6/5 C = 360

C = 300

Connor originally had $300, and Luisa $60.  Connor gave Luisa $120, and they both had $180.

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oksano4ka [1.4K]
We have an arithmetic progression:
Nth=an
an=a₁+(n-1)d
a₁ is the first term.
n=number of terms.
d=common difference

10,17,24,31...
a₁=10
d=a₂-a₁=17-10=7

Therefore:
Nth=an
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Therefore: the formula for the nth is, an=a+(n-1), in this case; an=7n+3,

To check:
a₁=7*1+3=10
a₂=7*2+3=17
a₃=7*3+3=24
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Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8?

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The evening host of a dinner dance reached into a bowl, mixed all the tickets around, and selected the ticket to award the grand
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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Treat this like compound interest:  Use A = P(1 + r)^t.

Here, P is the initial population and A is 3 times that, or 3P.  Since P = 20 people, 3P = 60 people,

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ln (1 + r) = ---------------

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