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marysya [2.9K]
1 year ago
5

If p → q is true, then ~ p → ~ q is __________ true. always sometimes never

Mathematics
1 answer:
Yuliya22 [10]1 year ago
6 0

Answer:

The correct answer is Never

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Find an explicit rule for the nth term of the sequence. -5, -25, -125, -625, ...
Keith_Richards [23]
An=a1(r)^(n-1)
a1=first erm
r=common ratio

firs term is -5
we times each term by 5 to get next term so r=5

a_n=-5(5)^{n-1} is the explicit formula
8 0
2 years ago
What is the common difference between the elements of the arithmetic sequence below?
fredd [130]
All numbers in each number add up to 9, i dont know if you understand me, 
for example:
1+8=9
2+2+5=9
2+7=9
.....

3 0
1 year ago
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Lisa is 10 centimeters taller than her friend Ian. Ian is 14 centimeters taller than Jim. Every month, their heights increase by
bekas [8.4K]
Let Lisa's height be x, Ian's be y and Jim's be z
x = 10 + y . . . (1)
y = 14 + z . . . (2)
y + 14 + z + 14 = 170 + x + 14
y + z - x = 170 + 14 - 28 = 156 . . . (3)
From (2), z = y - 14 . . . (4)
Putting (1) and (4) into (3) gives,
y + y - 14 - 10 - y = 156
y = 156 + 24 = 180

Therefore, Ian's height is 180 centimeters
5 0
2 years ago
What are the solutions of 8x2 = 6 + 22x? Check all of the boxes that apply.
Sholpan [36]
Transpose all the terms in the left hand side of the equation. The equation then becomes,
                         8x²  - 22x - 6 =0
Divide both sides of the equation by 2,
                        4x² - 11x - 3 = 0 

In this equation, A = 4, B = -11, and C = -3

With the variables identified, the quadratic equation can be used to identify the roots,
                         x = (-B +/- √B² - 4AC) / 2A
The values of x in the equation are,
                        <em> x = 3 and x = -1/4
</em>
<em />Thus, the one of the answer to this item is the third choice, x = 3. <em>
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6 0
2 years ago
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In a certain month, Oscar sells 6 cars more than Jackie. If together they sell 30 cars, how many cars did Jackie sell?
diamong [38]

Answer:

Jackie sold 12 cars.

Step-by-step explanation:

If we call the number of cars Oscar sold O, and the number of cars Jackie sold J, we can say the following:

O = J + 6

As Oscar sold 6 cars more than Jackie.

Together, they sold 30 cars.

O + J = 30

Since we know that:

O = J + 6

... we can put this into our previous equation.

O + J = 30

(J + 6) + J = 30

J + J + 6 = 30

2 * J + 6 = 30

Subtract 6 from both sides:

2 * J = 24

Divide both sides by 2:

J = 24 / 2

J = 12

Jackie sold 12 cars.

8 0
2 years ago
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