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2 years ago

7

How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x

minus 1.(x + 12) = 4x – 1

2 answers:

dmitriy555 [2]2 years ago

8 0

Answer:

Only one solution.

Step-by-step explanation:

We have to solve for x from a linear single variable equation of x.

We have to determine the number of the solution of the given equation.

The equation is $\frac{1}{2} (x + 12) = 4x - 1$

⇒ x + 12 = 8x - 2

⇒ 7x = 14

⇒ x = 2

So, there is only one solution of the given equation of x. (Answer)

Alika [10]2 years ago

3 0

Answer:

one solution

Step-by-step explanation:

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5 0

2 years ago

6 questions = 30 points someone please help me

eduard

Answer:

1)D

2)D

3)A

4)B

5)Cannot Answer - No data

6)C

7)C

6 Questions answered for 30 points.

Step-by-step explanation:

Answer for the 1st Question,

Area of a cylinder can be calculated by,

Area of the cylindrical part = $2\pi rL$

Area of the parts that cover the open parts of cylinder = $2\pi r^2$

Therefor Total are of the cylinder = $2\pi rL+2\pi r^2$

Area of the total cylinder = $2*3.14*6.8*14.2+2*3.14*6.8^2$

= $896.784$

<u>Therefor best estimate will be D) 923 in^2</u>

Answer for the 2nd Question,

ABC is a triangle.

By Pythagorean theorem it says,

$(AC)^2+(CB)^2=(AB)^2$

The distance from A to C = 6

The distance from C to B = 5

$(AC)^2=6^2=36$

$(CB)^2=5^2=25$

$(AC)^2+(CB)^2=(AB)^2=36+25=61$

Therefor $(AB)^2=61\\(AB)=\sqrt{61}$

<u>Therefor Answer is D) Sqr 61</u>

Answer to Question 3

To find the trend you can draw an imaginary line that fits the scatter plots.(I have attached a image drawing the imaginary lines)

Then the revenue can be calculated by calculating the area covered by the imaginary line drawn or area "under" the curve.

Area of the Store 1 = $\frac{1}{2} *(110+40)*110=8250$

Area of the Store 2= $\frac{1}{2} *110*80=4400$

Therefore Revenue from Store 1 = $8250

Revenue from Store 2 = $4400

<u>Answer is A) Store 1 has more sales revenue</u>

Answer for Question 4

$\frac{5}{12}=0.4167\\\frac{5}{11}=0.4545$

You can straight away discard answer D because it is less than both 5/12 and 5/11.

Also you can discard Answer C because 25/264 is very small (less than 1/10=0.1)

$\frac{11}{23} =0.4782$ , therefor this is not in between those two numbers.

Then it has to be $\frac{115}{264} =0.4356$

<u>Answer is B)</u>

Answer for question 6

The equation of a straight line is of the form $y=mx+c$

here m is the gradient and c is the intercept.

Find the intercept(c) by finding the y value when x value is 0, here it is +1.

Gradient (m) of the graph can be found by,

$\frac{y1-y2}{x1-x2} =\frac{7-3}{3-1} =2$

Therefor the equation of the graph is,

$y=2x+1$

<u>Answer is C</u>

Answer for question 7

$\frac{7}{8} =0.875$

$\frac{6}{9} =0.67$

We can discard answer A because the value is close to 0.5

We can discard answer B because 3/17 is a very small value (0.17)

$\frac{53}{72} =0.73$ , This falls between the above 2 numbers.

<u>Therefor answer is C</u>

5 0

2 years ago

Complete the square to rewrite y = x2 - 6x + 15 in vertex form. Then state

love history [14]

Since $x^2$ is the square of x and 6x is twice the product between x and 3, the second square must be 3 squared, i.e. 9.

So, if we think of 15 as 9+6, we have

$x^2-6x+9+6 = (x-3)^2+6$

Which is the required vertex form. This form tells us imediately that the vertex is the point (3,6).

Since the leading coefficient is 1, the parabola is facing upwards (it's U shaped), so the vertex is a minimum.

5 0

2 years ago

Almonds cost $5.20 per pound Raisins cost $2.75 per pound Priya spent $11.70 of buying almonds & raisins Equation: 5.20+2.75

murzikaleks [220]

Answer:

If she bought 2lbs of almonds, she bought 0.4lbs of raisins. If she bought 1lb of almonds, she can buy up to 2.36lbs of raisins. If she bought 0.64lbs of almonds, she can buy up to 1.9lbs of almonds.

Step-by-step explanation:

6 0

2 years ago

For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: $z=\frac{x-\mu}{\sigma}$

Here z is 2.42 and μ is 790, substitute the respective values as shown.

$2.42=\frac{1637-790}{\sigma}$

$\sigma=\frac{847}{2.42}$

$\sigma=350$

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0

2 years ago