Answer:
In kJ/kg.K - 1.005 kJ/kg degrees Kalvin.
In J/g.°C - 1.005 J/g °C
In kcal/ kg °C 0.240 kcal/kg °C
In Btu/lbm-°F 0.240 Btu/lbm degree F
Step-by-step explanation:
given data:
specific heat of air = 1.005 kJ/kg °C
In kJ/kg.K
1.005 kJ./kg °C = 1.005 kJ/kg degrees Kelvin.
In J/g.°C
In kcal/ kg °C
For kJ/kg. °C to Btu/lbm-°F
Need to convert by taking following conversion ,From kJ to Btu, from kg to lbm and from degrees C to F.
1.005 kJ/kg C = 0.240 Btu/lbm degree F
Answer:
The length of the longest 15% of Atlantic cod in this area is 53.79cm, roundeed to 2 decimal places.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.
In this problem, we have that:
A study conducted in 2012 found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 49.9 cm and a standard deviation of 3.74 cm, so .
What is the length in cm of the longest 15% of Atlantic cod in this area?
We have to find the value of X for the value of Z that has a pvalue of 0.85.
Looking at the zscore table, we have that Z = 1.04 has a pvalue of 0.8508. So, we have to find the value of X when .
So
The length of the longest 15% of Atlantic cod in this area is 53.79cm, roundeed to 2 decimal places.