Answer:
m∠QRT = 90°
m∠QRT = m∠SRT
Step-by-step explanation:
Triangle QST is isosceles with QT ≅ ST. In isoscels triangle QST, angles STR and RTQ are congruent.
RT is angle T bisector, so angles QTR and STR are congruent.
Consider two triangles QTR and STR. In these triangles:
By SAS postulate, these two triangles are congruent. Two congruent triangles have congruent corresponding sides, so
Angles QRT and SRT are supplementary (add up to 180°). Since these two angles are congruent, they have the same measure equal to
So, true options are
m∠QRT = 90°
m∠QRT = m∠SRT
For a better understanding of the solution provided please go through the diagram in the file attached.
Let ABCD be the rectangular yard. The diagonal d=17 meters. AD=8 meters. Therefore, the length of DC can be found by applying the Pythagorean theorem in the right triangle as:
meters.
Answer:
the P matrix you are looking for is P=(1/) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]]
Step-by-step explanation:
Answer:
For an orthogonal diagonalization of any matrix you have to:
1º) Find the matrix eigenvalues in a set order.
2º) Find the eigenvectors of each respective eigenvalues.
Tip: You can write the matrix A like A = D P
3º) D is the diagonal matrix with each eigenvalue (in order) in the diagonal.
4º) Write P as the normalized eigenvectors in order (in columns).
Tip 2: Remember, ·P = I, so if A =
D P, then:
P A = P
D P
= I D I = D
So the P we are looking for is the of the diagonalization.
Tip 3: In this case, A is a block matrix with null nondiagonal submatrixes, therefore its eigenvalues can be calculated by using the diagonal submatrixes. The problem is reduced to calculate the eigenvalues of A₁₁ = A ₂₂ = [[5 3],[3 5]]
Solving:
1º)the eigenvalues of A₁₁ are {8,2}, therefore the D matrix is
2º) the eigenvectors of A₁₁ are P₈= {[1 1]T} P₂= {[1 -1]T}, therefore normalizing the eigenvectors you obtain P = (1/) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]] (you can see that P =
in this case).
As said in "tip 2": P A = P
D P
= I D I = D
So the P obtained is the one you are looking for.
