Answer:
Step-by-step explanation:
find the attached below
If a cube-shaped cell is 3 units tall by 3 units wide and 3 units long, what is the cell's surface-area-to volume ratio?
1 answer:
The cube has 6 sides, each a square with dimensions 3 by 3,
the area of any of these squares is 3*3=9 square units.
The total area of the cube is 6*9 square units=54 square units
The volume of a cube with side length a is given by :
, thus the volume of the cube-shaped cell is 3*3*3=27 cube units.
(surface area):(volume)=54:27 = 2:1 =2
Answer:
the ratio of the numerical values is 2
(their ratio including units is 2/unit
the area of any of these squares is 3*3=9 square units.
The total area of the cube is 6*9 square units=54 square units
The volume of a cube with side length a is given by :
(surface area):(volume)=54:27 = 2:1 =2
Answer:
the ratio of the numerical values is 2
(their ratio including units is 2/unit
You might be interested in
We have been given a system of inequalities and an objective function.
The inequalities are given as:
And the objective function is given as:
In order to find the minimum value of the objective function at the given feasible region, we need to first graph the region.
The graph of the region is shown below:
From the graph, we can see that corner points of the feasible region are:
(x,y) = (15,30),(30,15) and (30,60).
Now we will evaluate the value of the objective function at each of these corner points and then we will compare which of those values is minimum.
Hence the minimum value of objective function is 975 and it occurs at x = 15 and y = 30
