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2 years ago

A circle is centered at the point -3 2 and passes through the point 1 and 5 the radius of the circle is blank units

Mathematics

1 answer:

photoshop1234 [79]2 years ago

7 0

Answer:

The radius of the circle is 5 units

Step-by-step explanation:

Given in the question,

centered point = (-3 , 2)

a point in the circle = (1,5)

To find the radius of circle we will use the circle equation

(x – h)² + (y – k)² = r²,

with the centre being at the point (h, k) and the radius being r.

Plug values in the equation

(1 – (-3))² + (5 – 2)² = r²

(1+3)² + (3)² = r²

4² + 3² = r²

25 = r²

r = √25

r = 5

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Let’s play Pick-A-Ball with replacement! There are 10 colored balls: 3 red, 4 white, and 3 blue. The balls have been placed into

Anettt [7]

Answer:

0.48

Step-by-step explanation:

There are 10 colored balls: 3 red, 4 white, and 3 blue.

You selected 2 balls at random. They may be

RR, WW, BB, RW, RB, WB, WR, BR, BW.

To find the probability of selecting the color of ball that you just selected, find this probability in each of previous cases:

RR: (One red ball left and 8 balls left in total)

$P_{RR}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}$

WW: (Two white balls left and 8 balls left in total)

$P_{WW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{2}{8}=\dfrac{1}{30}$

BB: (One blue ball left and 8 balls left in total)

$P_{BB}=\dfrac{3}{10}\cdot \dfrac{2}{9}\cdot \dfrac{1}{8}=\dfrac{1}{120}$

RW: (Two red and three white balls left and 8 balls left in total)

$P_{RW}=\dfrac{3}{10}\cdot \dfrac{4}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

RB: (Two red and two blue balls left and 8 balls left in total)

$P_{RB}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}$

WB: (Two blue and three white balls left and 8 balls left in total)

$P_{WB}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

WR: (Two red and three white balls left and 8 balls left in total)

$P_{WR}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

BR: (Two red and two blue balls left and 8 balls left in total)

$P_{BR}=\dfrac{3}{10}\cdot \dfrac{3}{9}\cdot \dfrac{4}{8}=\dfrac{1}{20}$

BW: (Two blue and three white balls left and 8 balls left in total)

$P_{BW}=\dfrac{4}{10}\cdot \dfrac{3}{9}\cdot \dfrac{5}{8}=\dfrac{1}{12}$

In total, the probability of selecting the color of ball that you just selected is

$\dfrac{1}{120}+\dfrac{1}{30}+\dfrac{1}{120}+2\cdot\dfrac{1}{12}+2\cdot \dfrac{1}{20}+2\cdot \dfrac{1}{12}=\\ \\=\dfrac{1}{120}+\dfrac{4}{120}+\dfrac{1}{120}+\dfrac{20}{120}+\dfrac{12}{120}+\dfrac{20}{120}=\dfrac{58}{120}=\dfrac{29}{60}\approx 0.48$

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Ahmed doubled his savings, then deposited another hundred dollars. Let s represent the amount he originally had in savings. Whic

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Answer:

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