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Vsevolod [243]
2 years ago
6

Jason practiced making soccer goals and kept track of the results. He missed 3 goals but made 9 in one practice session. What ca

n Jason predict regarding goals made if his next practice session has 24 tries?
Mathematics
2 answers:
yawa3891 [41]2 years ago
7 0
He can predict that he will make 18 goals.
Degger [83]2 years ago
6 0

Answer:

18 just toke the test

Step-by-step explanation:

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Jenny studied the characteristics of two species of bacteria. The number of bacteria of species A, A(t), after t hours is repres
Marina CMI [18]
<h3><u>Answer:</u></h3>

The function N(t) is given as:

N(t)=3+(0.25t)^3-8(1.06)^t

<h3><u>Step-by-step explanation:</u></h3>

Jenny studied the characteristics of two species of bacteria.

The number of bacteria of species A, A(t), after t hours is represented by the function:

A(t) = 5+(0.25t)^3

The number of bacteria of species B, B(t), after t hours is represented by the function:

B(t) = 2 + 8(1.06)^t

N(t) denotes the difference in the number of bacteria; hence N(t) is given by after t hours as:

N(t)=A(t)-B(t)

N(t)= 5+(0.25t)^3-(2 + 8(1.06)^t)

which on simplifying gives:

N(t)=5+(0.25t)^3-2-8(1.06)^t\\\\N(t)=5-2+(0.25t)^3-8(1.06)^t\\\\N(t)=3+(0.25t)^3-8(1.06)^t

Hence,

5 0
1 year ago
Read 2 more answers
Find the difference between the cash price and the payment plan and calculate the interest rate for the following questions.
vagabundo [1.1K]

Answer:

1).

Difference = $6

Interest rate= 4.03%

2).diffrence = $97

Interest rate = 14.37%

3). Difference = $7

Interest rate= 4.67%

4). difference= 191

Interest rate= 9.6%

5). Difference= 2.25

Interest rate= 3%

6). Difference=$ 302

Interest rate=9.12%

Step-by-step explanation:

1).$10 per months for 15 months

= 10*15=$150

PLus a down payment of $5= $155

Interest = 155-149= $6

Interest rate = 6/149*100= 4.03%

2.)$120.00 per month for 6 months

= 120*6=$ 720

Plus a down payment of $52=$772

Interest= 772-675= $97

Interest rate = 97/675 *100= 14.37%

3). $12.00 per month for 11 months

= 12*11= 132 plus down payment of $25

= $157

Interest= 157-150= $7

Interest rate=7/150 *100= 4.67%

4).$74.00 per month for 24 months

= 74*24=$1776

Plus a down payment of $400=$ 2176

Interest= 2176-1985= 191

Interest rate= 191/1985*100= 9.6%

5).$4.75 per week for 11 weeks

= 4.75*11=$52.25

Plus a down payment if $25

= 25+52.25=$ 77.25

Interest= 77.25-75= 2.25

Interest rate= 2.25/75 *100= 3%

6).$300 a month for 10 months

= 300*10= $3000

Plus a down payment of $600

= $3600

Interest=3600-3298= 302

Interest rate= 302/3298 *100=9.12%

5 0
1 year ago
A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w
sveta [45]

Answer:

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for business  

\hat p_A =\frac{75}{400}=0.1875 represent the estimated proportion for Business

n_A=400 is the sample size required for Business

p_B represent the real population proportion for non Business

\hat p_B =\frac{137}{500}=0.274 represent the estimated proportion for non Business

n_B=500 is the sample size required for non Business

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412  

(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318  

And the 95% confidence interval would be given (-0.1412;-0.0318).  

We are confident at 95% that the difference between the two proportions is between -0.1412 \leq p_A -p_B \leq -0.0318

7 0
1 year ago
Find the length of the leg of a right triangle with leg length b= 21.5 inches and the hypotenuse c= 31.9 inches. Use a calculato
sweet [91]

Answer:

23.6 (approximate value)

Step-by-step explanation:

  • a*a+b*b=c*c Pythagorean thereom
  • (21.5)^2 + b*b = (31.9)^2
  • b*b= 1017.61 - 462.25
  • √b*b= √555.36
  • b=23.6(approximate value)
8 0
2 years ago
Poiseuille's Law states that the volume, V, of blood flowing through an artery in a unit of time at a fixed pressure is directly
eimsori [14]

Answer:

11.58%

Step-by-step explanation:

The initial volume if blood flowing through the artery is given by

V=kr^4

To achieve a new volume of 155% (55% increase) of the initial volume, the new radius must be:

V'= 1.55V\\1.55V=k(r')^4\\1.55kr^4 = k(r')^4\\(\sqrt[4]{1.55}*r)^4=(r')^4 \\(1.1158*r)^4=(r')^4 \\r'=1.1158*r

Since the new radius is 1.1158 times larger than the initial radius, the percentage increased is:

I=(1.1158 - 1)*100\%\\I= 11.58\%

7 0
2 years ago
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