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sertanlavr [38]
2 years ago
5

Paul and his neighbors decided to build a fence along his farm. After three hours, they have 15 meters of fencing complete. They

decide to take a 2-hour break for lunch and then resume building the fence. After four more hours, they have a fence that is a total of 55 meters long. PLEASE HELP ME!!!! never been good with graphs,
the y-axis goes by 5's and goes all the way up to 55 starting from 5. the y-axis is the length of the fence in meters, and the x-axis goes to 10 by ones which is the number of hours
Mathematics
1 answer:
Goshia [24]2 years ago
8 0

Let the  be the time in hours, and  meters of fencing completed. 

We know that After three hours, they have 15 meters of fencing complete, our graph will go from the point (0,0) to the point (3,15). We also know that they decide to take a 2-hour break for lunch and then resume building the fence, so our graph will go from the point (3,15) to the the point (5,15). Finally, After four more hours, they have a fence that is a total of 55 meters long, so the final part of our graph will go from the point (5,15) to the point (9,55)


We can conclude that the graph of t vs y is:

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16.A guidance counselor is planning schedules for 30 students. Sixteen students say they want to take French, 16 want to take Sp
MariettaO [177]

Answer:7

Step-by-step explanation:

This can be solved by Venn-diagram

Given there  are total 5 students who want french and Latin

also 3 among them want Spanish,french & Latin

i.e. only 2 students wants both french and Latin only.

Also Student who want only Latin is 5

Thus Student who wants Latin and Spanish both only is 11-5-3-2=1

Students who want only Spanish is 8 Thus students who wants Spanish and French is 4

Similarly Students who wants Only French is 16-4-3-2=7

8 0
2 years ago
Read 2 more answers
If e = 9 cm and f = 40 cm, what is the length of g?
rewona [7]

(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.

Answer: D. 41 cm

There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,

a^2+b^2 = (b+1)^2

a^2 + b^2 = b^2 + 2b +1

a^2=2b+1

So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.

b = (a^2 - 1)/2

a=3, b=(3^2-1)/2=4, c=b+1=5

a=5, b=(5^2-1)/2 =12, c = 13

a=7, b=24, c=25

a=9, b=40, c=41

a=11, b=60, c=61

a=13, b=84, c=85

It's good to be able to recognize Pythagorean Triples when we see them.  

Otherwise we'd have to work the calculator:

√(9² + 40²) = √1681 = 41

8 0
2 years ago
Triangle J K L is shown. Angle J K L is a right angle. An altitude is drawn from point K to point M on side L J to form a right
kompoz [17]

Answer:

LJ=15\ units

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the length side KJ

In the right triangle JKM

Applying the Pythagoras Theorem

KJ^{2}=JM^{2}+KM^{2}

we have

JM=3\ units

KM=6\ units

substitute

KJ^{2}=3^{2}+6^{2}

KJ^{2}=45}

KJ=\sqrt{45}\ units

simplify

KJ=3\sqrt{5}\ units

step 2

Find the value of cosine of angle MJK in the right triangle JKM

cos(JKM)=JM/KJ

substitute the values

cos(JKM)=\frac{3}{3\sqrt{5}}

simplify

cos(JKM)=\frac{\sqrt{5}}{5} -----> equation A

step 3

Find the value of cosine of angle MJK in the right triangle JKL

cos(JKM)=KJ/LJ

we have

KJ=3\sqrt{5}\ units

cos(JKM)=\frac{\sqrt{5}}{5} ----> remember equation A

substitute the values

\frac{\sqrt{5}}{5}=\frac{3\sqrt{5}}{LJ}

Simplify

LJ=5(3)=15\ units

8 0
2 years ago
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Explain how you used the bar model in exercise 2 to solve the problem
lutik1710 [3]

We are given that Grandma has 14 red roses and 7 pink roses.

In order to represent them on bar modal, we need to make a bar with 14 identical sections for 14 red roses.

And for pink roses, we need to make a bar with 7 identical sections for 7 pink roses.

<em>From the bar graph, we can see that bar for red roses have 7 more boxes than bar of pink roses.</em>

<h3>Therefore,  she have 7 more red roses than pink roses.</h3>

3 0
2 years ago
Tran has a credit card with a spending limit of $2000 and an APR (annual percentage rate) of 12%. During the first month, Tran c
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Tran has a credit card with a spending limit of $2000 and an APR (annual percentage rate) of 12%. During the first month, Tran charged $450 and paid $150 of that in his billing cycle.

The expression which will find the amount of interest Tran will be charged after the first month is (0.01)(300)

Here 0.01 because it is 1 month tax. 300 is remaining amount as Tran used $450 but paid $150.

4 0
2 years ago
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