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kolezko [41]
2 years ago
9

The traffic engineer for a large city is conducting a study on traffic flow at a certain intersection near the city administrati

on building. The engineer will collect data on different variables related to the intersection each day for ten days. Of the following variables, which will be measured using continuous data?
(A)-The number of cars passing through the intersection in one hour
(B)-The number of pedestrians crossing the intersection in one hour
(C)-The number of bicyclists crossing the intersection in one hour
(D)-The number of food trucks that park within four blocks of the intersection
(E)-The number of minutes for a car to get from the intersection to the administration building
Mathematics
1 answer:
barxatty [35]2 years ago
8 0

Answer:

e) The number of minutes for a car to get from the intersection to the administration building

Step-by-step explanation:

Continuous Data:

Data that can take any value (an infinite number of values) within a certain range.

For example, the statistics of a group of people form continuous data, but the number of people in that group form discrete data.

Inglés

In this case, counting items such as cars, bicycles, people, are considered discrete data. They exclusively take integer values.

But time data can take continuous values.

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Answer:

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034

The estimated standard error is:

\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096

The confidence interval for the difference in proportions is

-0.028\leq p_1-p_2 \leq 0.096

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0
1 year ago
I am a multiple of 60 I am between 400 and 600 I am 40 away from a multiple of 100 who am I
EleoNora [17]

Answer:

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1 year ago
Describe the graph represented by the equation r=5/(3+2 sin theta).
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We have the following equation:

r= \frac{5}{3+2sin(\theta)}

If we graph this equation we realize that in fact this is an ellipse with major axis matching the y-axis. So we can recognize these characteristics:

1. Center of the ellipse: 

The midpoint C<span> of the line segment joining the foci is called the </span>center<span> of the ellipse. So in this exercise this point is as follows:
</span>
C(0, -2)

2. Length of major axis:

The line through the foci is called the major axis<span>, so in the figure if you go from -5, at the y-coordinate, and walk through this major axis to the coordinate 1, the distance you run is the length of the major axis, that is:</span>

6 \ units

3. Length of minor axis:

The line perpendicular to the foci through the center is called the minor axis. So in the figure if you go from -2, at the x-coordinate, and walk through this minor axis to the coordinate 2, the distance you run is the length of the minor axis, that is:

4 \ units

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Let's find c as follows:

c=\sqrt{a^{2}-b^{2}}=\sqrt{3^{2}-2^{2}}=\sqrt{5}

Then the foci are:

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f_{2}=(0, -\sqrt{5}-2)

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1 year ago
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Yea I don’t know sorry bye
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1 year ago
Work out the value of (6.8x10^2) x (1.3x10^-3)
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Answer:

0.884

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6.8x10^2 = 680

1.3x10^-3 = 0.0013

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