The ratio can be written in parts as shown below;
Then, 60 can be divided as shown below;
25kg:35kg
Answer:
Step-by-step explanation:
Answer:
The Median should be 89.5
And the mean should be 69.75
I hope that helped
Let
x-------> <span>the length of the pond
</span>y-------> the width of the pond
we know that
[volume of the pond]=area of the base*deep
area of the base=volume/deep
volume=72000 in³
deep=24 in
area of the base=72000/24------> 3000 in²
area of the base=x*y
3000=x*y-------> equation 1
x=2y-----> equation 2
substitute equation 2 in equation 1
3000=[2y]*y------> 2y²=3000-----> y²=1500------> y=38.7 in
x=2y----> x=2*38.7----> x=77.4 in
the answer is
the length of the pond is 77.4 in
the width of the pond is 38.7 in
Answer:
No, the Roger’s claim is not correct.
Step-by-step explanation:
We are given that Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and the median.
This statement by Roger is incorrect because the median is unaffected by the outlier value and only the mean value gets affected by the outlier value.
As the median represents the middlemost value of our dataset, so any value which is an outlier will be either at the start or at the end will not the median value. So, the median will not likely change when an outlier is added to a small data set.
Now, the mean is the average of all the data set values, that is the sum of all the observations divided by the number of observations. The mean will get affected by the outlier value because it take into account each and every value of the data set.
Hence, the mean will likely to change greatly when an outlier is added to a small data set.
