Answer:
StartFraction 8 Over 25
Step-by-step explanation:
What is the product of StartFraction 4 Over 5 EndFraction times two-fifths?
Mathematically =
StartFraction 4 Over 5 EndFraction = 4/5
Two- fifths = 2/5
Hence,
The product of StartFraction 4 Over 5 EndFraction times two-fifths
= 4/5 × 2/5
= 8/25
The correct option =
StartFraction 8 Over 25 EndFraction
Answer: 15.7 minutes
Step-by-step explanation:
Let x be the time in the beginning (in minutes).
Given: The track team is trying to reduce their time for a relay race.
First they reduce their time by 2.1 minutes.
Then they are able to reduce that time by 10
If their final time is 3.96 minutes, then
x-t1-t2= 3.6
x= 3.6+ t1+ t2
x= 3.6+ 2.1+ 10
x= 15.7
Hence, their beginning time was 15.7 minutes.
We have that the spring is going to have a sin or a cos equation. We have that the maximum distance of the spring is 6 inches and it is achieved at t=0. Let's fix this as the positive edge. Until now, we have that the function is of the form:
6sin(at+B). We have that the period is 4 minutes and hence that the time component in the equation needs to make a period (2pi) in 4 minutes. Thus 4min*a=2p, a=2p/4=pi/2. In general, a=2pi/T where a is this coefficient, T is the period. Finally, for B, since sin(pi/2)=1, we have that B=pi/2 because when t=0, we have that 6sin(B)=6. Substituting, we have f(t)=6sin(pi*t/2+pi/2)=6cos(pi*t/2)
by trigonometric identities.
2010 47 +ten thousand split decide and
, where r is the radio. In this case, the volume of the sphere will be
, which is also equal to
.