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wariber [46]
2 years ago
8

What types of concurrent constructions are needed to find the orthocenter of a triangle? A. intersection of the lines drawn perp

endicular to each side of the triangle through its midpoint B. intersection of the lines drawn to bisect each vertex of the triangle C. intersection of the lines drawn from each vertex of the triangle and perpendicular to its opposite side D. intersection of the lines drawn to the midpoint of each side of the triangle to its opposite vertex
Mathematics
1 answer:
finlep [7]2 years ago
4 0

Answer: Hello! The answer to your question is B, the intersection of the lines drawn to bisect each vertex of the triangle. Hope this helped! Please pick my answer as the Brainliest!

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The distance of a golf ball from the hole can be represented by the right side of a parabola with vertex (−1, 8). The ball reach
sukhopar [10]

Answer:

The required equation is:

y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4

Explanation:

Let us assume that the hole is at y = 0m, with x as the time.

From the question we have (-1s, 8m) as the vertex (here x being the time variable is supposed to be in seconds and y being the distance variable is supposed to be in meters)

At x = 1s, the ball gets to the hole, therefore we have point (1s, 0m)

We know that the vertex of the parabola y = ax² + bx + c is at

x =\frac{-b}{2a}

therefore we have:

-1 = \frac{-b}{2a}

We then have the following equations:

8 = a\times -1^2 + b\times -1 + c

0 = a\times -1^2 + b\times 1 + c

-1 = \frac{-b}{2a}

From the 3rd equation we have

1 X 2a = b.

Therefore we have:

8 = a\times -1^2 - 1\times 2a\times1 + c

0 = a\times 1^2 + 1 \times2a\times 1 + c

We can simplify both equations and get:

8 = a\times( -1^2 - 2s^2) + c = -a\times 3^2 + c

0 = a\times(1^2 + 2^2) + c = a\times 3^2 + c

The first equation now becomes:

8 = -a\times 3 - a\times 3 = -a\times 6

a = frac{8}{-6} = -\frac{4}{3}

With a, we can find the values of c and b.

c = -a\times3 = -(-\frac{4}{3})*3 = 4

b = 1\times 2a = 1\times 2(-\frac{4}{3})= -\frac{8}{3}

Then the equation is:

y = -\frac{4}{3}t^2 -\frac{8}{3}t + 4

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2 years ago
Eula needs to buy binders that cost $4 each and notebooks that cost $2 each. She has $20. The graph of the inequality 4x + 2y ≤
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She has to buy both binders and notebooks. So, you have to take into account that she has to have both. The closest you can get to $20 while still getting notebooks, is to buy 4 binders. 4 times 4 equals 16. So, she can get 4 binders and 2 notebooks, because then, 2 times 2 equals 4 and 16 plus 4 equals 20.
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2 years ago
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The cost of hiring a surfboard involves an up-front fee plus an hourly rate. Three hours of hire costs $50 and 7 hours costs $90
siniylev [52]

Answer:

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If ΔONP is dilated from point N by a scale factor of segment NL over segment NP, which additional transformation could determine
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Answer:

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Step-by-step explanation:

This will show the similarity between the two triangles angles.

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What is the equation of the line? Iready
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Answer:

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