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wariber [46]
2 years ago
8

What types of concurrent constructions are needed to find the orthocenter of a triangle? A. intersection of the lines drawn perp

endicular to each side of the triangle through its midpoint B. intersection of the lines drawn to bisect each vertex of the triangle C. intersection of the lines drawn from each vertex of the triangle and perpendicular to its opposite side D. intersection of the lines drawn to the midpoint of each side of the triangle to its opposite vertex
Mathematics
1 answer:
finlep [7]2 years ago
4 0

Answer: Hello! The answer to your question is B, the intersection of the lines drawn to bisect each vertex of the triangle. Hope this helped! Please pick my answer as the Brainliest!

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2. Which situation does have a final value of 0?
professor190 [17]

Answer:

C

Step-by-step explanation:

7 0
2 years ago
Can someone help please??
Nady [450]

Answer:

The scores in order from least likely to most likely is 8, 3, 4, and 5.

Step-by-step explanation:

1. Calculate the probability of the spinner adding up to 1, 2, 3, 4, .... 8

You will get:

2 (1/16)

3 (2/16)

4 (3/16)

5 (4/16)

6 (3/16)

7 (2/16)

8 (1/16)

2. Given the scores from the problem, the probability of each number is 3 (2/16), 4 (3/16), 5 (4/16), and 8 (1/16).

3. With this, we can determine the scores in order from least likely to most likely is 8, 3, 4, and 5.

8 0
2 years ago
Which graph matches the equation y+3=2(x+3)?
Vlad1618 [11]

Answer:

The graph that includes points (-3,-3) and (0,3)

Step-by-step explanation:

In the pictures attached, the options are shown.

The equation:

y+3=2(x+3)

has the point-slope form, which is:

y-y₁=m(x-x₁)

where (x₁, y₁) is a point on the line and <em>m</em> is its slope. This means that (-3,-3) is on the line. To know the y-intercept of the line, we have to replace x = 0 into the equation, as follows:

y+3=2(0+3)

y+3 = 6

y = 6 - 3

y = 3

Then, point (0, 3) is on the line.

8 0
2 years ago
Please help me answer this ASAP! The two-way table shows the number of ninth and tenth graders who prefer going to sporting even
Elis [28]
<h2>Answer</h2>

0.43

<h2>Explanation</h2>

Remember that RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so SumOfAllFrecuencies=6+8=14. Let's replace the values:

RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

RelativeFrecuency=\frac{6}{14}

RelativeFrecuency=0.4285

And rounded to the nearest hundredth:

RelativeFrecuency=0.43

4 0
2 years ago
Jake made a total of 7 copies at a copy shop, with some being black-and-white copies and some being color copies. Black-and-whit
Arada [10]
Jake spent a total of 70 cents.
b = black-and-white = 8 cents
c = color = 15 cents

70 = 8b + 15c

he made a total of 7 copies
b + c = 7

system of equation:
70 = 8b + 15c
b + c = 7

--------------------------

b + c = 7
b + c (-c) = 7 (-c)
b = 7 - c

plug in 7 - c for b

70 = 8(7 - c) + 15c
Distribute the 8 to both 7 and - c (distributive property)

70 = 56 - 8c + 15c
Simplify like terms

70 = 56 - 8c + 15c
70 = 56 + 7c

Isolate the c, do the opposite of PEMDAS: Subtract 56 from both sides

70 (-56) = 56 (-56) + 7c
14 = 7c

divide 7 from both sides to isolate the c

14 = 7c
14/7 = 7c/7
 c = 14/7
 c = 2

c = 2
---------------

Now that you know what c equals (c = 2), plug in 2 for c in one of the equations.
b + c = 7
c = 2
<em>b + (2) = 7
</em><em />Find b by isolating it. subtract 2 from both sides
b + 2 = 7
b + 2 (-2) = 7 (-2)
b = 7 - 2
b = 5

Jake made 5 black-and-white copies, and 2 color copies

hope this helps
8 0
2 years ago
Read 2 more answers
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