Question

Marcy has $150 to buy packages of hot dogs and hamburgers for her booth at the carnival. At her local grocery store she found packages of hot cost $6 and packages of hamburgers cost $20. She has to use her entire budget of $150.
a. Solve the equation for b (burgers)
b. Solve the equation for d (hot dogs)

Answer 1

Total money that Marcy possess = $ 150

Cost of one hot dog= $ 6

Cost of one Hamburger = $ 20

If Marcy buys only Hamburger having cost b , then

b = $\frac{150}{20}=7.50$= 7 Hamburger

If Marcy buys only Hotdogs having cost d , then

d = $\frac{150}{6}=25$

And if Marcy buys both Hamburger and Hot dogs both, then

6 d + 20 b ≤ 150 ,b>0, d>0

3 d + 10 b≤ 75, b= Burger,→ X axis, d = Hot Dogs , →→Y axis

Plotting it on two dimensional plane

The positive integral value of x and y are the solution of the equation represented by : 3 y +10 x =75, for example y= 15 hamburger, and x =3 hot dog,  is one solution of this line which is representation of burger and hot dog.

Answer 2

6d + 20b = 150 
d=5
b=6