Ask question

Ask question

All categories

1 year ago

14

If you vertically stretch the exponential function f(x)=2^x by a factor of 5 what is the equation of the new function

2 answers:

Montano1993 [528]1 year ago

4 0

Just mult. both sides of that equation by 5:

g(x) = 5*2^x

Natali [406]1 year ago

3 0

Answer: $f(x)=5*2^{x}$

Step-by-step explanation: When we multiply a function by a positive constant, we get a function whose graph is stretched or compressed vertically in relation to the graph of the original function. If the constant is greater than 1, we get a vertical stretch; if the constant is between 0 and 1, we get a vertical compression. So,if we want to stretch the given function by a factor of 5, we just need to multiply such function by 5:

Original function:

$f(x)=2^{x}$

Stretched function:

$f(x)=5*2^{x}$

You might be interested in

luis has a cooler filled with cans of soda. For every 5 cans of coke there are 3 cans of sprite. If there are 25 cans of coke, h

faltersainse [42]

for every 5 is 3, so 25*3= equals 75,

5 0

1 year ago

Read 2 more answers

Find the length of the leg of a right triangle with leg length b= 21.5 inches and the hypotenuse c= 31.9 inches. Use a calculato

sweet [91]

Answer:

23.6 (approximate value)

Step-by-step explanation:

a*a+b*b=c*c Pythagorean thereom
(21.5)^2 + b*b = (31.9)^2
b*b= 1017.61 - 462.25
√b*b= √555.36
b=23.6(approximate value)

8 0

1 year ago

The telephone company is planning to introduce two new types of executive communications systems that it hopes to sell to its la

cluponka [151]

Answer:

x = 31 hundred dolars and

y = 91/2 = 45.5 hundred dolars

Step-by-step explanation:

Given

R(x) = (40−8x+5y)*x + (50+9x−7y)*y

C(x) = (40−8x+5y)*10 + (50+9x−7y)*29

We can use the equation

P(x) = R(x) - C(x)

where

P(x) is the profit

R(x) is the revenue

and C(x) is the costs

In order to maximize the telephone company's profit, we apply

P'(x) = R(x)' - C(x)' = 0

⇒ R(x)' = ((40−8x+5y)*x + (50+9x−7y)*y)' = (40x-8x²+14xy+50y-7y²)'

⇒ C(x)' = ((40−8x+5y)*10 + (50+9x−7y)*29)' = (1850+181x-153y)'

⇒ P'(x) = -8x²-7y²-141x+203y+14xy-1850

The first-order partial derivatives of these functions are

Px(x,y) = -16x-141+14y

Py(x,y) = -14y+203+14x

Setting these equal to zero and solving we obtain:

-16x+14y-141 = 0

14x-14y+203=0

we get the solution

x = 31 and y = 91/2 = 45.5

Finally, the company should produce 3100 units of the first system, and 4550 units of the second system.

8 0

2 years ago

6. Matthew is planning to build a right triangular

saul85 [17]

The answer to this question will be B

8 0

2 years ago

A group of 10 students participate in chess club, karate club, or neither.

Afina-wow [57]

Total number of students = 10

As we have to find

P(A/B) = Probability( A when B has happend)

P(A/B)= P(A intersection B)/P(B)

According to given figure only yolanda and Rob are in both club

Therefore,P(A intersection B) $=\frac{2}{10}$

Number of student in karate club =6

P(B) $= \frac{6}{10}$

P(A/B) $= \frac{2}{10}\div{\frac{6}{10}$

Converting division into multiplication by reciprocating the term after division

P(A/B) $= \frac{2}{10}\times{\frac{10}{6}$

On solving we get ,

P(A/B) $= \frac{2}{6}$

P(A/B) $=\frac{1}{3}$

P(A/B) $=0.33$

8 1

2 years ago