If you vertically stretch the exponential function f(x)=2^x by a factor of 5 what is the equation of the new function
2 answers:
Answer:
Step-by-step explanation: When we multiply a function by a positive constant, we get a function whose graph is stretched or compressed vertically in relation to the graph of the original function. If the constant is greater than 1, we get a vertical stretch; if the constant is between 0 and 1, we get a vertical compression. So,if we want to stretch the given function by a factor of 5, we just need to multiply such function by 5:
Original function:
Stretched function:
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Once you plot the data points, make a trendline. You are given with options. If you want a linear function, then you will have a linear model with a function equation of y = 0.2907x + 2.2643. It has a correlation coefficient of 0.9595. That's a strong correlation already. The R² value tells how good your model fits the data points. If you want to increase the R², a better model would be a quadratic function with the equation, y = -0.0209x²+0.506x+2.0232. As you can see the R² increase even more to 0.9992.
Once you plot the data points, make a trendline. You are given with options. If you want a linear function, then you will have a linear model with a function equation of y = 0.2907x + 2.2643. It has a correlation coefficient of 0.9595. That's a strong correlation already. The R² value tells how good your model fits the data points. If you want to increase the R², a better model would be a quadratic function with the equation, y = -0.0209x²+0.506x+2.0232. As you can see the R² increase even more to 0.9992.
Answer:
procedure always produces 6
Step-by-step explanation:
Let 'n' be the unknown number
Add 4 to the number : n+4
multiply the sum by 3.
multiply the sum n+4 by 3
Now subtract 6, so we subtract 6 from 3n+12
finally decrease the difference by the tripe of the original number
triple of original number is 3n
so the procedure always produces 6