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Alika [10]
2 years ago
13

The graph of y=3x^2-3x-1 is shown. Use the graph to find estimates for the solutions of i)3x^2-3x+2=2 ii) 3x^2-3x-1=x+1

Mathematics
1 answer:
AlexFokin [52]2 years ago
7 0

Answer:

i) (0, 2) and (1, 2), ii) (0.333, 1.333) and (1, 2).

Step-by-step explanation:

i) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = 2, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = 2

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0, 2) and (1, 2)

ii) Let be y=3\cdot x^{2}-3\cdot x -1, if 3\cdot x^{2}-3\cdot x +2 = x+1, which is equivalent to the following system of equations:

y = 3\cdot x^{2}-3\cdot x +2

y = x+1

Now, this system is now represented by means of a graphing tool and whose outcome is attached below. There are two solutions: (0.333, 1.333) and (1, 2)

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Answer:

a) 0.07203

b) 0.0189

c) 0.973

Step-by-step explanation:

Probability of making one shot, for the player = 70% = 0.70

Probability of NOT making a shot = 1 - 0.70 = 0.30

Assuming that the shots are​ independent

a) Misses for the first time on his fifth attempt ​

For him to miss on his for the first time on his fifth attempt, he has to make the first four shots

The required probability = (0.7)⁴(0.3) = 0.07203

b) Makes his first basket on his fourth shot

For him to make his first basket on the fourth shot, he has to miss the first three shots.

Required probability = (0.3)³(0.7) = 0.0189

​c) Makes his first basket on one of his first 3 shots

This is a sum of probabilities; that is, he could make the first basket on the first shot, or miss on the first shot and make the second shot or miss on the first two shots and make the basket on the third shot.

Required probability

= (0.70) + (0.3×0.7) + (0.3×0.3×0.7)

= 0.70 + 0.21 + 0.063 = 0.973

Hope this Helps!!!

3 0
2 years ago
The table represents the height of a ball thrown up from the roof of a building, h(t), in meters, t seconds after it is thrown u
Anna [14]
• The ball is at the same height as the building between 8 and 10 seconds after it is thrown. TRUE - the height is zero somewhere in that interval, hence the ball is the same height from which it was thrown, the height of the roof of the building.

• The height of the ball decreases and then increases. FALSE - at t=2, the height is greater than at t=0.

• The ball reaches its maximum height about 4 seconds after it is thrown. TRUE - the largest number in the table corresponds to t=4.

• The ball hits the ground between 8 and 10 seconds after it is thrown. FALSE - see statement 1.

• The height of the building is 81.6 meters. FALSE - the maximum height above the building is 81.6 meters. Since the ball continues its travel to a distance 225.6 meters below the roof of the building, the building is at least that high.


1. TRUE
2. False
3. TRUE
4. False
5. False
9 0
2 years ago
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A person's resting heart rate is typically between 60 and 100 beats per minute. Noah looks at his watch, and counts 8 heartbeats
sweet-ann [11.9K]

Answer:

h=48

Step-by-step explanation:

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6 0
1 year ago
A frog catches insects for his lunch. The frog likes to eat flies and mosquitoes in a certain ratio, which is shown in the diagr
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Answer:

ON MONDAY:  35 mosquitos.

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Step-by-step explanation:

As you can see in the diagram, the frog eats 3 flies for every 7 mosquitoes (for lunch). Then you can expresed this ratio as following:

3:7 or \frac{3}{7}

Based on the table:

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-If the frog eats 14 mosquitoes on tuesday, then the number of flies that it eats can be calculated as following:

\frac{3}{7}=\frac{flies}{14}\\\\flies=\frac{14*3}{7}\\\\flies=6

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