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Alborosie
1 year ago
6

A country's population in 1993 was 94 million. in 1999 in was 99 million. estimate the population in 2005 using the exponential

growth formula. round your answer to the nearest million. P=Ae^kt
Mathematics
1 answer:
Jet001 [13]1 year ago
7 0
The initial population is
P₀ = 94 million in 1993

The growth formula is
P(t) = P_{0}e^{kt}
where P(t) is the population (in millions) after t years, measured from 1993.
k = constant.

Because P(5) = 99 million (in 1999), 
94e^{5k} = 99 \\e^{5k}=1.0532 \\ 5k = ln(1.0532) \\ k = 0.010367

In the year 2005, t = 12 years, and
P(12)=94e^{0.010367*12} = 106.45

Answer: 106 million (nearest million)

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