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siniylev [52]
2 years ago
14

Tonya is twice Kevin's age. In three years, Tonya will be 17. And in another three years, Uncle Rob will be three times Tonya’s

age.
Today, Kevin is ____years old, and Uncle Rob ___is years old.
Mathematics
2 answers:
zhuklara [117]2 years ago
7 0
To find Kevin's age, subtract 17 by 3 to find how old Kevin is, which is 7. Then, to find Uncle rob's age, add 17 plus 3 to get 20, then multiply that by 3 to see how old Uncle Rob will be, which is 60.Then, subtract 6 from 60 to get 54.The final answer is that Kevin is 7 years old, and Uncle Rob is 54 years old. Hope this helps!
bezimeni [28]2 years ago
6 0

Answer:

Today, Kevin is 7 years old, and Uncle Rob 54 is years old.

Step-by-step explanation:

Tonia will be 17 years old in 3 years,  so, to get Tonia´s age now, make 17-3. She is 14 years old today.

As Tonia twice the age of Kevin,  so,  Kevin´s age is the actual age of Tonia divided by 2. That will be 14/2=7

To get Uncle´s age ,  we start at 17 years of Tonia, We must added it 3 years,  so she will be 20 years old. Remember we have added 6 years from today.  

Then,  if uncles will be three times Tonia´s age, that will be =20*3=60.

Now,  6 years before,  he is 60-6 =54 years

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Answer:

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Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

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