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Elena L [17]
2 years ago
13

The rule is applied to ΔABC. On a coordinate plane, 5 triangles are shown. Triangle A B C has points (2, negative 4), (4, negati

ve 4), (4, negative 2). Triangle 1 has points (negative 4, 2), (negative 4, 4), (negative 2, 4). Triangle 2 has points (negative 3, 3), (negative 1, 3), (negative 1, 1). Triangle 3 has points (1, 1), (1, 3), (3, 3). Triangle 4 has points (2, 4), (4, 2), (4, 4). Which triangle shows the final image? 1 2 3 4
Mathematics
2 answers:
vfiekz [6]2 years ago
8 0

Answer:

Consider triangle ABC with vertices at points A(2,-4), B(4,-4) and C(4,-2).

1. The rotation  acts with the rule:

Then:

2. The reflection across the y-axis has a rule:

So,

Triangle A''B''C'' is exactly the same as tiangle from figure 1.

Answer: correct choice is 1.

PLZ brainliest answer

Step-by-step explanation:

Luden [163]2 years ago
5 0

Answer:

A(2,-4), B(4,-4) and C(4,-2).

Step-by-step explanation:

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Group of baseball fans can see home plate from a 40 meter tall building outside the stadium. The angle of vision has a tangent o
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Answer:

17.78 meters

Step-by-step explanation:

Let

x ----> the horizontal distance, in meters, to home plate

\theta ----> the angle of vision

we know that

tan(\theta)=\frac{40}{x} ----> by TOA (opposite side divided by the adjacent side)

we have

tan(\theta)=\frac{9}{4}

substitute

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solve for x

x=40(4)/9\\x=17.78\ m

5 0
2 years ago
m∠RSW = 2x + 16; m∠WSV = 3x + 2 m∠UST = 2x; m∠VSU = m∠UST Find m∠WSV. please answer this geotemrty is really hard
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Answer: 56 degree

Explanation:

2x + 16 + 3x + 2 + 2x + 2x = 180 (straight angle)

9x + 18 = 180
9x = 162
x = 162/9
x = 18

But WSV = 3x + 2

And x = 18

=> 3(18) + 2
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8 0
2 years ago
Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea
asambeis [7]

Answer:

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Step-by-step explanation:

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n\geq (\frac{z\sigma}{ME})^2

Where:

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  • ME is the desired margin of error.

We substitute our given values to calculate the sample size:

n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23

Hence, the smallest desired sample size is 23

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N + d = 30 and 5n + 10d =220 
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