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Archy [21]
1 year ago
12

What is the circumference of a circle with a diameter of 45 centimeters?

Mathematics
2 answers:
madam [21]1 year ago
6 0
Circumference, C = πd
d = diameter.

C = π*45

C = 45π

C ≈ 45*3.142

C≈ 141.39

C ≈ 141.4

Option D.
zysi [14]1 year ago
3 0
It is 141.4 centimetres. This is because the circumference is obtained by multiplying pi with the diameter.
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Maya can run 18 miles in 3 hours, and she can bike 18 miles in 2 hours.
Aloiza [94]

Answer:

36

Step-by-step explanation:

if it is two hours then half of it is 9

so 18 + 9 = 27 which is how many miles she biked

6 is the number of miles she ran

so u times it by 1.5

27 + 9 = 36

4 0
2 years ago
Read 2 more answers
Four different prime numbers, each less than 20, are multiplied together. What is greatest possible result?
valentinak56 [21]

Answer:

46,189

Step-by-step explanation:

The prime numbers that are less than 20 are :

1,2,3,5,7,11,13,17,19

to get the greatest value, we multiply the four numbers with the largest values i.e

11 x 13 x 17 x 19 = 46,189

8 0
2 years ago
Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random sample of
nikitadnepr [17]

Answer:

a) Reject H₀

b) [0.31; 3.35]

Step-by-step explanation:

Hello!

a) The objective of this example is to compare if the population means of the production rate of the assembly lines A, B and C. To do so the data of the production of each line were recorded and an ANOVA was run using it.

The study variable is:

Y: Production rate of an assembly line.

Assuming that the study variable has a normal distribution for each population, the observations are independent and the population variances are equal, you can apply a parametric ANOVA with the hypothesis:

H₀ μ₁= μ₂= μ₃

H₁: At least one of the population means is different from the others

Where:

Population 1: line A

Population 2: line B

Population 3: line C

α: 0.01

This test is always one-tailed to the right. The statistic is the Snedecor's F, constructed as the MSTr divided by the MSEr if the value of the statistic is big, this means that there is a greater variance due to the treatments than to the error, this means that the population means are different. If the value of F is small, it means that the differences between populations are not significant ( may differ due to error and not treatment).

The critical region is:

F_{k-1;n-k; 1-\alpha } = F_{2;15; 0.99} = 6.36

If F ≥ 3.36, the decision is to reject the null hypothesis.

Looking at the given data:

F= \frac{MSTr}{MSEr}= 11.32653

With this value the decision is to reject the null hypothesis.

Using the p-value method:

p-value: 0.001005

α: 0.01

The p-value is less than the significance level, the decision is to reject the null hypothesis.

At a level of 5%, there is significant evidence to say that at least one of the population means of the production ratio of the assembly lines A, B and C is different than the others.

b) In this item, you have to stop paying attention to the production ratio of the assembly line A to compare the population means of the production ratio of lines B and C.

(I'll use the same subscripts to be congruent with part a.)

The parameter to estimate is μ₂ - μ₃

The populations are the same as before, so you can still assume that the study variables have a normal distribution and their population variances are unknown but equal. The statistic to use under these conditions, since the sample sizes are 6 for both assembly lines, is a pooled-t for two independent variables with unknown but equal population variances.

t=  (X[bar]₂ - X[bar]₃) - ( μ₂ - μ₃) ~t_{n_2+n_3-2}

Sa√(1/n₂+1/n₃)

The formula for the interval is:

(X[bar]₂ - X[bar]₃) ± t_{n_2+n_3-2; 1 - \alpha /2}* Sa\sqrt{*\frac{1}{n_2} + \frac{1}{n_3} }

Sa^{2} = \frac{(n_2-1)*S_2^2+ (n_3-1)*S_3^2}{n_2+n_3-2}

Sa^{2} = \frac{(5*0.67)+ (5*0.7)}{6+6-2}

Sa^{2} = 0.685

Sa= 0.827 ≅ 0.83

t_{n_2+n_3-2;1-\alpha /2}= t_{10;0.995} = 3.169

X[bar]₂ = 43.33

X[bar]₃ = 41.5

(43.33-41.5) ± 3.169 * *0.83\sqrt{*\frac{1}{6} + \frac{1}{6} }

1.83 ± 3.169 * 0.479

[0.31; 3.35]

With a confidence level of 99% you'd expect that the difference of the population means of the production rate of the assemly lines B and C.

I hope it helps!

8 0
2 years ago
A student estimates the weight of astronauts on the moon by multiplying their weight by the decimal 0.16666....what fraction can
Elden [556K]

Let x = 1.66666... ....(1)

Multiply both sides of equation (1) by 10.

10x = 1.666666.... .... (2)

Multiply both sides of equation (1) by 100.

100x = 16.66666....... (3)

Subtract equation (2) from equation (3)

100x - 10x = 16.66666...- 1.66666...

90x = 15

x= \frac{15}{90}  = \frac{1}{6}

Hence, the required fraction form is \frac{1}{6} .... Answer.


3 0
2 years ago
Read 2 more answers
After the closing of the mill, the town of Sawyerville experienced a decline in its population.
ycow [4]

Step-by-step explanation:

P(t) = 12,000 (2)^(-t/15)

9,000 = 12,000 (2)^(-t/15)

0.75 = 2^(-t/15)

ln(0.75) = ln(2^(-t/15))

ln(0.75) = (-t/15) ln(2)

-15 ln(0.75) / ln(2) = t

t = 6.23

5 0
2 years ago
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